   Chapter 8.3, Problem 16E

Chapter
Section
Textbook Problem

Using Wallis's Formulas In Exercises 15-20, use Wallis’s Formulas to evaluate the integral. ∫ 0 π / 2 cos 6 x   d x

To determine

To calculate: The value of definite integral given as, 0π2cos6xdx using Wallis’s formula.

Explanation

Given:

The expression is 0π2cos6xdx.

Formula used:

Wallis’s formula is given as,

If n is odd (n3), then,

0π2cosnxdx=(23)(45)(67)...(n1n)

If n is even (n2), then,

0π2cosnxdx=(12)(34)(56)...(n1n)(π2)

Calculation:

Consider the integral be equal to I,

I=0π2

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