Chapter 8.3, Problem 21E

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# In Exercises 17 to 30, use the formula A = 1 2 a P to find the area of the regular polygon described.Find the area of a regular hexagon whose sides have length 6 cm.

To determine

To find:

The area of a regular hexagon.

Explanation

1) Any radius of a regular polygon bisects the angle at the vertex to which it is drawn.

2) Any apothem of a regular polygon bisects the side of the polygon to which it is drawn.

3) The measure of any central angle of a regular polygon of n sides is given by c=360âˆ˜n

4) The perimeter of a regular polygon is given by P = ns, where n is the number of sides and s is the length of any side.

5) The area of a regular hexagon with apothem a and perimeter P is given by A=12(aP).

Calculation:

Consider a regular hexagon ABCDEF with QE as radius and QG as apothem.

It is given that the side of the regular hexagon ABCDEF is 6 cm i.e., AB = BC = CD = DE = EF = FA = 6 cm

Any apothem of a regular polygon bisects the side of the polygon to which it is drawn.

Therefore, GE= GD

Now, DF = GE + GD

â‡’6=GE+GDâ‡’6=2GDâ‡’GD=3â€‰cm

The regular hexagon has 6 sides.

Use the formula of central angle, c=360âˆ˜n

Substitute n = 6 in c=360âˆ˜n.

c=360âˆ˜6=60âˆ˜

Therefore, âˆ EQD=60âˆ˜

With âˆ EQD=60âˆ˜ and QE=QD, Î”QED is an equiangular and equilateral triangle.

Therefore, QE = QD = 6 cm

Any radius of a regular polygon bisects the angle at the vertex to which it is drawn

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