Chapter 8.3, Problem 36E

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# Regular octagon ABCDEFGH is inscribed in a circle whose radius is 7 2 2 cm. Considering that the area of the octagon is less than the area of the circle and greater than the area of the square ACEG, find the two integers between which the area of the octagon must lie.(Note: For the circle, use A = π r 2 with π ≈ 22 7 .)

To determine

To find:

The two integers between which the area of the octagon must lie.

Explanation

1) The diameter of the circle is twice the radius.

2) The area of the circle is given by, A=Ï€r2 where r is the radius of the circle.

3) The area of the square is given by, A=d22 where d is diagonal of the square.

Calculation:

It is given that the radius of the circle is 722â€‰cm.

Use the formula to find the area of the circle, A=Ï€r2

Substitute r=722 in A=Ï€r2

Acircle=Ï€(722)2=49Ï€2=492Ã—227=77â€‰cm2

The diameter of the circle is given by 72â€‰cm

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