   Chapter 8.3, Problem 5E

Chapter
Section
Textbook Problem

# Finding an Indefinite Integral Involving Sine and Cosine In Exercises 3-14, find the indefinite integral. ∫ sin 3 x cos 2 x   d x

To determine

To calculate: The value of indefinite integral given as, sin3xcos2xdx.

Explanation

Given:

The expression is sin3xcos2xdx.

Formula used:

Integration of xn is given as,

xndx=xn+1n+1+C

Derivative of cosx with respect to x is given as,

ddx(cosx)=sinx

Calculation:

Consider the integral to be I,

I=sin3xcos2xdx

Simplify it to a form where the power rule can be used,

I=sin3xcos2xdx=sin2xcos2xsinxdx=(1cos2x)cos2xsinxdx=cos2xsinxdxcos4xsinxdx

For the int

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