   Chapter 8.5, Problem 18SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 17-20, evaluate the definite integral. ∫ − 2 1 2 x ( x 2 − 5 ) 2 d x

To determine

To calculate: The value of definite integral 212x(x25)2dx.

Explanation

Given Information:

The provided definite integral is 212x(x25)2dx.

Formula used:

Formula of definite integral of un.

undu=un+1n+1+C

Here, n is the integer.

Square of difference of two numbers:

(ab)2=a2+b22ab

Calculation:

The provided definite integral is,

212x(x25)2dx

Simplify with the help of Square of difference of two numbers (ab)2=a2+b22ab.

212x(x25)2dx=212x((x2)2+(5)22x2(5))dx=212x(x4+2510x2)dx=21(2x5+50x20x3)dx

Use the formula of undu=un+1n+1+C to solve the above expression

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