   Chapter 8.5, Problem 39E ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
1 views

# Use the results from Exercises 36 and 37 to find the exact length of the radius of the inscribed circle for a triangle with sides of lengths a) 7 , 24 and 25 b) 9 , 10 and 17

To determine

(a)

To find:

The length of radius of inscribed circle for a triangle.

Explanation

Formula:

Radius of inscribed circle for right angled triangle:

If a, b and c are the lengths of sides of right angled triangle (c is the length of hypotenuse), then the length of radius r of circle inscribed in a right angled triangle is r=aba+b+c.

Radius of inscribed circle for any other triangle:

If a, b and c are the lengths of sides of triangle, then the length of radius r of circle inscribed in a triangle is r=2×s(s-a)(s-b)(s-c)a+b+c

Where s is the semi perimeter of the triangle which is given by s=a+b+c2.

Calculation:

First, let’s check whether the triangle is a right angled triangle or not.

From the given lengths of sides of triangle, the longest side measures 25.

252=625.

The sum of squares of remaining two sides =72+242=49+576=625

To determine

(b)

To find:

The length of radius of inscribed circle for a triangle.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Find more solutions based on key concepts 