   Chapter 8.5, Problem 41E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Evaluating a Definite Integral In Exercises 39-46, evaluate the definite integral. See Example 6. ∫ π / 2 2 π / 3 sec 2 x 2 d x

To determine

To calculate: The value of definite integral π/22π/3sec2x2dx.

Explanation

Given Information:

The provided integral is π/22π/3sec2x2dx.

Formula used:

Write the formula of definite integral of absec2nudu.

absec2nudu=[tannun]ab

Here, n is the any positive integer.

The provided integral is,

π/22π/3sec2x2dx

Integrate with the help of absec2nudu formula.

π/22π/3sec2x2dx=[tanx21/2

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