10th Edition

Ron Larson + 1 other

ISBN: 9781285057095

Textbook Problem

Using Partial Fractions In Exercises 3-20, use partial fractions to find the indefinite integral.

∫ 2 9 x 2 − 1 d x

To determine

To calculate: The indefinite integral for the given function, by using partial fractions.

The integral function is ∫29x2−1dx.

Formula used:

∫1xdx=lnx+C.

Calculation:

Consider following indefinite integral

The above integral function can be written as,

29x2−1=2(3x−1)(3x+1)

Now by using partial fraction method we get,

2(3x−1)(3x+1)=A3x−1+B3x+1=A(3x+1)+B(3x−1)(3x−1)(3x+1)

By simplifying further we get,

2=A(3x+1)+B(3x−1)

2=A(3(−13)+1)+B(3(−13)−1)<

Check out a sample textbook solution.

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Using Partial Fractions In Exercises 3-20, use partial fractions to find the indefinite integral.

∫ 2 9 x 2 − 1 d x

Chapter 8 Solutions

Additional Math Solutions

MathCalculusCalculus10th Edition

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Calculus

Using Partial Fractions In Exercises 3-20, use partial fractions to find the indefinite integral. ∫ 2 9 x 2 − 1 d x

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Chapter 8 Solutions

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Calculus Calculus 10th Edition

Using Partial Fractions In Exercises 3-20, use partial fractions to find the indefinite integral.

∫ 2 9 x 2 − 1 d x