   Chapter 8.CR, Problem 14CR Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Solutions

Chapter
Section Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

One side of a triangle is 10 cm longer than a second side, and the third side is 5 cm longer than the second side. The perimeter of the triangle is 60 cm.a) Find the lengths of the three sides.b) Find the area of the triangle.

To determine

(a)

To find:

The lengths of the three sides.

Explanation

Calculation:

Given:

Let b be the length of second side of a triangle. One side is 10 cm longer than second side, so its length is b+10.

Another side is 5 cm longer than length of second side. That is length of third side is b+5

By using the above information we can a triangle as shown below.

We'll call the sides a, b, and c.a=b+10c=b+5

The perimeter of the triangle (P) = 60 cm

P=a+b+c60=b+10+b+b+560=3b+153b=6015

To determine

(b)

To find:

Find the area of the triangle.

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