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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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In the practice of chemistry one of the most important calculations concerns the masses of products expected when particular masses of reactants are used in an experiment. For example, chemists judge the practicality and efficiency of a reaction by seeing how close the amount of product actually obtained is to the expected amount. Using a balanced chemical equation and an amount of starting material of your choice, summarize and illustrate the various steps needed in such a calculation for the expected amount of product.

Interpretation Introduction

Interpretation:

Using a balanced chemical equation and an amount of starting material, the steps needed to calculate the expected amount of product should be summarized.

Concept Introduction:

The balanced equation for a chemical reaction gives the same type of information. It indicates the relative numbers of reactants and products involved in the reaction. Using the equation permits us to determine the amounts of reactants needed to give a certain amount of product or predict how much product can be made from a given quantity of reactants.

Explanation

Given information:

The balanced equation for a chemical reaction gives the same type of information. It indicates the relative numbers of reactants and products involved in the reaction. Using the equation permits us to determine the amounts of reactants needed to give a certain amount of product or predict how much product can be made from a given quantity of reactants.

S(s)+O2(g)SO2(g)

Step 1 : First number of moles of each reactant should be calculated.

Number of moles of S = 1.00 g32.07 g/mol = 0.0312 mol

Number of moles of O2 = 1.00 g32.00 g/mol = 0.0313 mol

Step 2 : Limiting reagent should be decided.

Mole ratio between the two reactants is 1:1. So, to react with 0.0312 mol of S, 0

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