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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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For a balanced chemical equation of your choice, and using 25.0 g of each of the reactants in your equation, illustrate and explain how you would determine which reactant is the limiting reactant. Indicate clearly in your discussion how the choice of limiting reactant follows from your calculations.

Interpretation Introduction

Interpretation:

For a balance chemical equation of our choice and using 25.0 g of each of the reactants, illustrate what is a limiting agent.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

The limiting reactant in a particular reaction has due to following properties:

  1. Limiting reactant completely reacted in a particular reaction.
  2. Limiting reactant determines the amount of the product in mole.
Explanation

Limiting reactant is defined as the reactant which is completely consumed in the chemical reaction and it also determines the amount of the product.

If any reactant left after competitions of reaction, then it is said to be excess reactant.

For an example: the balance chemical equation for production of methyl salicylate is as follows:

C7H6O3  + CH3OHC8H8O3 + H2O     Reactants              Products 

According to the problem both reactants are present in same amount which are 25.0 g.

First, calculate the number of moles of all reactants with the use of their molar mass as follows:

Moles of C7H6O3   =Amount of C7H6O3 Molar mass of C7H6O3   =25.0 g C7H6O3  138.12 g/ mole C7H6O3  =0.18 moles of C7H6O3

Moles of CH3OH   =Amount of CH3OH Molar mass of CH3OH  =25.00 g CH3OH  32

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