   # For each of the following unbalanced equations, indicate how many moles of the first product are produced if 0.625 mole of the second product forms. State clearly the mole ratio used for each conversion. msp; KO 2 ( s ) + H 2 O ( l ) → KOH ( s ) msp; SeO 2 ( g ) + H 2 Se ( g ) → H 2 O ( g ) msp; CH 3 CH 2 OH ( l ) + O 2 ( g ) → CH 3 CHO ( a q ) + H 2 O ( l ) msp; Fe 2 O 3 ( s ) + Al ( s ) → Fe ( l ) + Al 2 O ( s ) ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
Chapter 9, Problem 16QAP
Textbook Problem
101 views

## For each of the following unbalanced equations, indicate how many moles of the first product are produced if 0.625 mole of the second product forms. State clearly the mole ratio used for each conversion.msp;  KO 2 ( s ) + H 2 O ( l ) → KOH ( s ) msp;  SeO 2 ( g ) + H 2 Se ( g ) → H 2 O ( g ) msp;  CH 3 CH 2 OH ( l ) + O 2 ( g ) → CH 3 CHO ( a q ) + H 2 O ( l ) msp;  Fe 2 O 3 ( s ) + Al ( s ) → Fe ( l ) + Al 2 O ( s )

Interpretation Introduction

(a)

Interpretation:

Number of moles of the first product produced if 0.625 mole of the second product forms in the given unbalanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

### Explanation of Solution

Balanced chemical equation

4 KO2(s)+ 2 H2O(l) 3 O2 (g)+ 4 KOH(s)

According to the balanced equation, mole ratio between KOH( s ) and O2 ( g ) = 3 mol O2(g)4 mol KOH(s)

So, Amount of O2 ( g ) produced = 0

Interpretation Introduction

(b)

Interpretation:

Number of moles of the first product produced if 0.625 mole of the second product forms in the given unbalanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

Interpretation Introduction

(c)

Interpretation:

Number of moles of the first product produced if 0.625 mole of the second product forms in the given unbalanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

Interpretation Introduction

(d)

Interpretation:

Number of moles of the first product produced if 0.625 mole of the second product forms in the given unbalanced chemical equation should be calculated.

Concept Introduction:

Balanced chemical equation shows us identities of reactants and products and how much reactants and products participate in the reaction. The coefficients in the balanced equation enable us to calculate how much product we can get from a given quantity of reactant or to get a definite amount of product, how much reactants we need. The ratio of these coefficients is the useful one, not the individual coefficient. This ratio is known as Mole ratio.

For a substance, number of moles is related to mass and molar mass of the substance as follows:

n=mM

Here, m is mass of substance in g and M is molar mass of substance in g/mol.

Thus, from number of moles, mass can be calculated as follows:

m=n×M.

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