   Chapter 9, Problem 18CR ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
5 views

# For each of the following balanced equations, calculate how many grams of each product would form if 12.5 g of the reactant listed first in the equation reacts completely (there is an excess of the second reactant).msp;  SiC ( s ) + 2 Cl 2 ( g ) → SiCl 4 ( l ) + C ( s ) msp;  Li 2 O ( s ) + H 2 O ( l ) → 2 LiOH ( a q ) msp;  2 Na 2 O 2 ( s ) + 2 H 2 O ( l ) → 4 NaOH ( a q ) + O 2 ( g ) msp;  SnO 2 ( s ) + 2 H 2 ( g ) → Sn ( s ) + 2 H 2 O ( l )

Interpretation Introduction

(a)

Interpretation:

The amount of product in given reaction should be calculated.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Explanation

The limiting reactant in a particular reaction has due to following properties:

1. Limiting reactant completely reacted in a particular reaction.
2. Limiting reactant determines the amount of the product in mole.

If any reactant left after competitions of reaction, thus it is said to excess reactant.

The balance chemical equation is as follows:

SiC(s)+2Cl2(g)SiCl4(l)+C(s)

Given:

Amount of first reactant = 12.5 g

Calculation:

Number of moles of SiC calculated as follows:

Number of moles=mass in gmolarmass=1.25 g40.11 g/mol=0.0312 moles SiC

Amount of product in gram calculated as follows:

0.0312 moles SiC×1

Interpretation Introduction

(b)

Interpretation:

The amount of product in the given reaction should be calculated.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(c)

Interpretation:

To calculate the amount of product in given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(d)

Interpretation:

The amount of product in given reaction should be calculated.

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

For example, the reaction between lead sulphide and oxygen is as follows:

2 PbS +  3 O22PbO +  2SO2  Reactants            Products

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

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