   Chapter 9, Problem 1P

Chapter
Section
Textbook Problem

An 81.5·kg man stands on a horizontal surface. (a) What is the volume of the man’s body if his average density is 985 kg/m3? (b) What average pressure from his weight is exerted on the horizontal surface. If the man’s two feet have a combined area of 4.50 × 10−9 m3?

(a)

To determine
The volume of the man’s body if his average density of 985kg/m3 .

Explanation
The definition of density of an object is the ratio of mass to its volume that is ρ=M/V and this expression is rearranged for the volume of the object.

Given info: The mass of the man is 81.5kg and the density of the man is 985kg/m3 .

The formula for the volume of the man is,

V=Mρ

• M is mass of the man.
• ρ is average density of the man.

Substitute 81.5kg for M and 985kg/m3 for ρ to find V .

V=81.5kg985kg/m3=8

(b)

To determine
The average pressure from his weight exerted on the horizontal surface.

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