   Chapter 9, Problem 27P

Chapter
Section
Textbook Problem

A cube of wood having an edge dimension of 20.0 cm and a density of 650. kg/m3 floats on water. (a) What is the distance from the horizontal top surface of the cube to the water level? (b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface?

(a)

To determine
The distance from the horizontal top surface of the cube to the water level.

Explanation
The cube of wood submerge until the buoyant force equals the weight the wood block and after the reach of equilibrium, the sum of forces on the cube of wood is Fy=0Bwwood=ρwaterg[(sh)s2]ρwoodgs3 and this expression is rearranged for the distance h .

Given info: Density of water is 103kg/m3 , density of wood cube is 650kg/m3 , and side of the cube is 20.0cm .

h=s(1ρwoodρwater)

• s is side of the cube of wood.
• ρwood is density of the wood

(b)

To determine
The mass of the lead that placed on the cube.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 