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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

An object weighing 300 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 265 N. Immersed in oil, the object appears to weigh 275 N. Find (a) the density of the object and (b) the density of the oil.

(a)

To determine
The density of the object.

Explanation
The density of the object is ρobject=m/V and here the mass of the object is m=(Wobject)air/g . Now volume of the object would be B=(ρwaterV)g (Wobject)air(Wobject)water=(ρwaterV)g and this expression is rearranged for the volume of the object and then used for the density of the object.

Given info: The weight of the object in air is 300N and after immersed in water, the weight of the object is 265N , acceleration due to gravity is 9.80m/s2 , and density of water is 103kg/m3 .

The formula for the density of the object is,

ρobject=(Wobject)air(Wobject)air(Wobject)waterρwater

  • (Wobject)air is weight of the object in air

(b)

To determine
The density of the oil.

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