   # A person obtains approximately 2 .5 × 10 3 Calories a day from his or her food. How much energy is that in calories? joules? kilowatt-hours? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 9, Problem 32E
Textbook Problem
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## A person obtains approximately 2 .5 × 10 3 Calories a day from his or her food. How much energy is that incalories?joules?kilowatt-hours?

Interpretation Introduction

Interpretation:

The energy 2500 Calories/day is to be calculated in the given units.

Concept Introduction:

Unit conversion is defined as the process in which multiple steps are there and is used to convert the unit of measurement for the same given quantity. It is determined by multiply with a conversion factor.

The fraction in which numerator and denominator, both are the same quantities but are determined in different units is known as a conversion factor.

### Explanation of Solution

a) Calories into cal.

Conversion of Calories into cal is as follows:

E= given Cal×1000 cal1 Cal(2500 Cal×1000 cal1Cal)=2.5×106 cal

Therefore, the result of the conversion is 2.5×106 cal.

b) calories into joules.

Conversion of calories into joules is as follows:

1 gram calorie=4.18 joule, Hence, conversion factor is as:

4.18 J1 cal

E= given Cal×1000 cal1 Cal×4.18 J1 cal(2500 Cal×1000 cal1 Cal×4.18 J1 cal)=1.0×107 J

Hence, the result of the conversion is 1.0×107.

c) calories into kWh

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