   # Small quantities of ammonia gas can be generated in the laboratory by heating an ammonium salt with a strong base. For example, ammonium chloride reacts with sodium hydroxide according to the following balanced equation: :math&gt; NH 4 Cl ( s ) + NaOH ( s ) → NH 3 ( g ) + NaCl ( s ) + N 2 O ( g ) at mass of ammonia gas is produced if 1.39 g of ammonium chloride reacts completely? ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
Chapter 9, Problem 34QAP
Textbook Problem
75 views

## Small quantities of ammonia gas can be generated in the laboratory by heating an ammonium salt with a strong base. For example, ammonium chloride reacts with sodium hydroxide according to the following balanced equation::math> NH 4 Cl ( s ) + NaOH ( s ) → NH 3 ( g ) + NaCl ( s ) + N 2 O ( g ) at mass of ammonia gas is produced if 1.39 g of ammonium chloride reacts completely?

Interpretation Introduction

Interpretation:

The mass of ammonia gas produced from 1.39 g of ammonium chloride reacts completely should be calculated.

Concept Introduction:

The balanced chemical equation is as follows:

NH4Cl(s)+NaOH(s)NH3(g)+NaCl(s)+H2O(g)

From the balanced chemical reaction, 1 mol of ammonium chloride reacts with 1 mol of sodium hydroxide to give 1 mol of ammonia, 1 mole of sodium chloride and 1 mol of water.

Mass of ammonia gas can be calculated from its number of moles which can be calculated from number if moles of ammonium chloride.

### Explanation of Solution

To calculate the mass of ammonia gas, first calculate number of moles of ammonium chloride as follows:

n=mM

Molar mass of ammonium chloride is 53.5 g/mol thus,

n=1.39 g53.5 g/mol=0.026 mol

From the balanced chemical reaction, 1 mol of ammonium chloride gives 1 mol of ammonia gas thus, 0

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