# Assume that electricity costs 15 cents per kilowatt- hour. Calculate the yearly cost of operating each of the following: a home computer that consumes 2.5 kWh per week a pool pump that consumes 300 kWh per week a hot tub that consumes 46 kWh per week a clothes dryer that consumes 20 kWh per week

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

Chapter
Section

### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 9, Problem 36E
Textbook Problem
13 views

## Assume that electricity costs 15 cents per kilowatt- hour. Calculate the yearly cost of operating each of the following:a home computer that consumes 2.5 kWh per weeka pool pump that consumes 300 kWh per weeka hot tub that consumes 46 kWh per weeka clothes dryer that consumes 20 kWh per week

Interpretation Introduction

Interpretation:

The yearly cost of operating each of the given devices is to be determined.

Concept introduction:

Unit conversion is defined as the process in which multiple steps are used to convert the unit of measurement for the same given quantity. It is determined by multiplication with a conversion factor.

The fraction in which numerator and denominator are the same quantities but are determined in different units, is known as a conversion factor.

### Explanation of Solution

a) A home computer that consumes 2.5 kWh per week

The electricity cost is 15 cents per kilowatt-hour.

In one year, there are 52 weeks. In 52 weeks, the electricity used in kilowatt-hour is as follows:

In 1year=52 weekFor 1year=2.5 kWh1 week×52 week1 yearFor 1year=130 kWh

The cost of electricity for one kilowatt-hour is 15 cents. It is divided by 100 to convert in dollars. The number of a kilowatt-hour is multiplied with cost per kilowatt-hour as follows:

yearly cost=130 kWh×$0.15kWh=$20

Therefore, the yearly cost of home computer is $20. b) A pool pump that consumes 300 kWh per week The electricity cost is 15 cents per kilowatt-hour. In one year, there are 52 weeks. In 52 weeks, the electricity used in kilowatt-hour is as follows: In 1year=52 weekFor 1year=300 kWh×52 week1 yearFor 1year=15600 kWh The cost of electricity for one kilowatt-hour is 15 cents. It is divided by 100 to convert in dollars. The number of a kilowatt-hour is multiplied with cost per kilowatt-hour as follows: yearly cost=15600 kWh×$0.15kWh=$2340 Therefore, the yearly cost for a pool pump is$2340.

c) A hot tube consumes 46 kWh per week

The electricity cost is 15 cents per kilowatt-hour

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