BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Solutions

Chapter
Section
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

When a person inhales, air moves down the bronchus (windpipe) at 15 cm/s. The average How speed of the air doubles through a constriction in the bronchus. Assuming incompressible flow, determine the pressure drop in the constriction.

To determine
The pressure drop in the constriction.

Explanation
Use Bernoulli’s equation for the pressure drop in constriction (ignoring the very small change in vertical position) is P1P2=(1/2)ρ(v22v12)=(3/2)ρv12 since the flow speed in the constriction is 2v1 .

Given info: The density of air is 1.29kg/m3 and the flow speed of the air in the bronchus is 15×102m/s .

The formula for the pressure drop in the constriction is,

ΔP=32ρv12

  • ρ is density of air.
  • v1 is flow speed of air.

Substitute 1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

A built environment can support physical activity with a. safe biking and walking lanes. b. public parks. c. fr...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

How may our senses be enhanced?

An Introduction to Physical Science

How does an ionic bond form?

Biology: The Dynamic Science (MindTap Course List)