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Calculate the amount of carbon dioxide (in kg) emitted into the atmosphere by the complete combustion of a 15.0 gallon tank of gasoline. Do this by following these steps: Assume that gasoline is composed of octane ( C 8 H 18 ) . Write a balanced equation for the combustion of octane. Determine the number of moles of octane contained in a 15.0 gallon tank of gasoline (1 gallon = 3.78 L). Octane has a density of 0.79 g/mL. Use the balanced equation to convert from moles of octane to moles of carbon dioxide, then convert to grams of carbon dioxide, and Finally to kg of carbon dioxide.

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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 9, Problem 49E
Textbook Problem
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Calculate the amount of carbon dioxide (in kg) emitted into the atmosphere by the complete combustion of a 15.0 gallon tank of gasoline. Do this by following these steps:

Assume that gasoline is composed of octane ( C 8 H 18 ) . Write a balanced equation for the combustion of octane.

Determine the number of moles of octane contained in a 15.0 gallon tank of gasoline (1 gallon = 3.78 L). Octane has a density of 0.79 g/mL.

Use the balanced equation to convert from moles of octane to moles of carbon dioxide, then convert to grams of carbon dioxide, and Finally to kg of carbon dioxide.

Interpretation Introduction

Interpretation:

The balanced equation for the combustion of octane is to be written and the number of moles of octane to be determined and the moles of octane to be converted finally to kg of carbon dioxide.

Concept introduction:

Gasoline is an engine fuel used in vehicles that is made from crude oil and other petroleum liquids. 

Carbon dioxide is a colorless gas that consists of carbon atoms bonded with two oxygen atoms.

The density of a substance is defined as the measurement of mass per unit volume. It is calculated as: density=massvolume.

Octane is an organic molecule with the molecular formula C8H18. The combustion of any hydrocarbon chain forms a large amount of water and carbon dioxide gas.

Conversion factor for liter to milliliter is 1 L1000 mL.

Conversion factor for gram to kilogram is 1 kg1000 g.

Explanation of Solution

a) A balance equation for the combustion of octane.

Octane is an alkane with the molecular formula C8H18, which has 8 carbons and 18 hydrogen molecules. The combustion of octane, or any hydrocarbon, releases carbon dioxide gas and water molecules.

The combustion of octane is as follows:

2 C8H18+25 O2Δ18 H2O+16 CO2

This is the balanced equation for the combustion of octane.

b) The number of moles of octane in a 15.0 gasoline tank of gasoline.

The number of moles of octane in a 15.0 gallon tank of gasoline is calculated as follows:

The density of octane (given) is 0.79 g/mL.

The number of moles can be calculated as follows:

Number of moles=given massmolar mass

The molar mass of octane is 114 g.

n=(15.0 gal×3.78 L1 gal×1000 ml1 L×0.79 g1 mL×1 mol114 g)=393 moles C8H18

Therefore, the number of moles of octane is 393 moles

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