   # The amount of CO 2 in the atmosphere is 0 .04% (0 .04% = 0 .0004 L CO 2 /L atmosphere). The world uses the equivalent of approximately 4 .0 × 10 12 kg of petroleum per year to meet its energy needs. Determine how long it would take to double the amount of CO 2 in the atmosphere due to the combustion of petroleum. Follow each of the steps outlined to accomplish this: a. We need to know how much CO 2 is produced by the combustion of 4 .0 × 10 12 kg of petroleum. Assume that this petroleum is in the form of octane and is combusted according to the following balanced reaction: 2C 8 H 18 ( L ) + 25O 2 ( g ) → 16CO 2 ( g ) + 18H 2 O ( g ) By assuming that O 2 is in excess, determine how many moles of CO 2 are produced by the combustion of 4 .0 × 10 12 kg of C 8 H 18 . This will be the amount of CO 2 produced each year. b. By knowing that 1 mol of gas occupies 22.4 L, determine the volume occupied by the number of moles of CO 2 gas that you just calculated. This will be the volume of CO 2 produced per year. c. The volume of CO 2 presently in our atmosphere is approximately 1 .5×10 18 L. By assuming that all CO 2 produced by the combustion of petroleum stays in our atmosphere, how many years will it take to double the amount of CO 2 currently present in the atmosphere from just petroleum combustion? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 9, Problem 50E
Textbook Problem
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## The amount of CO 2 in the atmosphere is 0 .04% (0 .04% = 0 .0004 L CO 2 /L atmosphere). The world uses the equivalent of approximately 4 .0 × 10 12 kg of petroleum per year to meet its energy needs. Determine how long it would take to double the amount of CO 2 in the atmosphere due to the combustion of petroleum. Follow each of the steps outlined to accomplish this:a. We need to know how much CO 2 is produced by the combustion of 4 .0 × 10 12 kg of petroleum. Assume that this petroleum is in the form of octane and is combusted according to the following balanced reaction: 2C 8 H 18 ( L )  + 25O 2 ( g )   → 16CO 2 ( g )  + 18H 2 O  ( g ) By assuming that O2 is in excess, determine how many moles of CO 2 are produced by the combustion of 4 .0 × 10 12 kg of C 8 H 18 . This will be the amount of CO 2 produced each year.b. By knowing that 1 mol of gas occupies 22.4 L, determine the volume occupied by the number of moles of CO 2 gas that you just calculated. This will be the volume of CO 2 produced per year.c. The volume of CO 2 presently in our atmosphere is approximately 1 .5×10 18 L. By assuming that all CO 2 produced by the combustion of petroleum stays in our atmosphere, how many years will it take to double the amount of CO 2 currently present in the atmosphere from just petroleum combustion?

Interpretation Introduction

Interpretation:

The number of moles of CO2, the volume occupied by the number moles of CO2 gas, and the number of years required to double the amount of CO2 are to be calculated.

Concept Introduction:

Mole is the unit for calculating large quantities of small units, such as atoms and molecules.

Carbon dioxide is a colorless and odorless gas.

A small amount of carbon dioxide is essential for sustaining life on the earth.

### Explanation of Solution

a) Number of moles of CO2 are produced by the combustion of 4×1012Kg of C8H18.

The amount of CO2 present in the atmosphere is 0.04% and the world uses 4×1012Kg of petroleum per year.

The reaction is as follows:

2C8H18(l)+25O2(g)16CO2(g)+18H2O(g).

The equation for the reaction of C8H18 with O2 is as follows:

2C8H18(l)+25O2(g)16CO2(g)+18H2O(g)

The mass of C8H18 is converted into grams as follows:

1Kg=1000gThemassoftheC8H18ingrams=4.0×1012×1000g=4.0×1015g

The moles of C8H18 are calculated using the expression as follows:

Moles of C8H18=GivenMassMolecularMass.

Substitute the value of given mass and molecular mass in the above expression.

Moles of C8H18=4.0×1015gC8H18114.2gC8H18=3.5×1013mole.

From the above equation, 2 moles of C8H18 will produce 16 moles of CO2. Therefore, moles of CO2 will be 216 of the moles of C8H18

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