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PhysicsCollege Physics11th Edition

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Chapter 9, Problem 69P
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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Solutions

Chapter
Section
Problem 1CQ
Problem 2CQ
Problem 3CQ
Problem 4CQ
Problem 5CQ
Problem 6CQ
Problem 7CQ
Problem 8CQ
Problem 9CQ
Problem 10CQ
Problem 11CQ
Problem 12CQ
Problem 13CQ
Problem 14CQ
Problem 15CQ
Problem 16CQ
Problem 1P
Problem 3P
Problem 4P
Problem 5P
Problem 6P
Problem 7P
Problem 8P
Problem 9P
Problem 10P
Problem 11P
Problem 12P
Problem 13P
Problem 14P
Problem 15P
Problem 16P
Problem 17P
Problem 18P
Problem 19P
Problem 20P
Problem 21P
Problem 22P
Problem 23P
Problem 24P
Problem 25P
Problem 26P
Problem 27P
Problem 28P
Problem 29P
Problem 30P
Problem 31P
Problem 32P
Problem 33P
Problem 34P
Problem 35P
Problem 36P
Problem 37P
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Problem 50P
Problem 51P
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Problem 55P
Problem 56P
Problem 57P
Problem 58P
Problem 59P
Problem 60P
Problem 61P
Problem 62P
Problem 63P
Problem 64P
Problem 65P
Problem 66P
Problem 67P
Problem 68P
Problem 69P
Problem 70P
Problem 71P
Problem 72P
Problem 73P
Problem 74P
Problem 75P
Problem 76P
Problem 77AP
Problem 78AP
Problem 79AP
Problem 80AP
Problem 81AP
Problem 82AP
Problem 83AP
Problem 84AP
Problem 85AP
Problem 86AP
Problem 87AP
Problem 88AP
Problem 89AP
Problem 90AP
Problem 91AP
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

For safety in climbing, a mountaineer uses a nylon rope that is 50. m long and 1.0 cm in diameter . When supporting a 90.-kg climber, the rope clongates 1.6 m. Find its Young’s modulus.

To determine
The Young’s modulus of the nylon rope.

Explanation
Yong’s modulus is defined as Y=stress/strain=(F/A)/(ΔL/L0) and the cross-sectional area of the rope is A=πr2=π(d/2)2 . The tension in the rope is equal to the weight of the climber that is F=W=mg

Given info: The diameter of the rope is 1.0 cm , length of the rope is 50 m , mass of the climber is 90 kg , the elongation of the nylon rope is 1.6 m , and acceleration due to gravity is 9.80 m/s2 .

The formula for the Young’s modulus of the rope is,

Y=4mgL0πd2ΔL

  • m is mass of the climber.
  • g is acceleration due to gravity.
  • L0 is length of the rope.
  • d is diameter of the rope.
  • ΔL is elongation of the rope.

Substitute 90 kg for m , 9

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Sect-9.2 P-9.1QQSect-9.3 P-9.2QQSect-9.4 P-9.3QQSect-9.4 P-9.4QQSect-9.5 P-9.5QQSect-9.5 P-9.6QQSect-9.6 P-9.7QQCh-9 P-1CQCh-9 P-2CQCh-9 P-3CQ
Ch-9 P-4CQCh-9 P-5CQCh-9 P-6CQCh-9 P-7CQCh-9 P-8CQCh-9 P-9CQCh-9 P-10CQCh-9 P-11CQCh-9 P-12CQCh-9 P-13CQCh-9 P-14CQCh-9 P-15CQCh-9 P-16CQCh-9 P-1PCh-9 P-3PCh-9 P-4PCh-9 P-5PCh-9 P-6PCh-9 P-7PCh-9 P-8PCh-9 P-9PCh-9 P-10PCh-9 P-11PCh-9 P-12PCh-9 P-13PCh-9 P-14PCh-9 P-15PCh-9 P-16PCh-9 P-17PCh-9 P-18PCh-9 P-19PCh-9 P-20PCh-9 P-21PCh-9 P-22PCh-9 P-23PCh-9 P-24PCh-9 P-25PCh-9 P-26PCh-9 P-27PCh-9 P-28PCh-9 P-29PCh-9 P-30PCh-9 P-31PCh-9 P-32PCh-9 P-33PCh-9 P-34PCh-9 P-35PCh-9 P-36PCh-9 P-37PCh-9 P-38PCh-9 P-39PCh-9 P-40PCh-9 P-41PCh-9 P-42PCh-9 P-43PCh-9 P-44PCh-9 P-45PCh-9 P-46PCh-9 P-47PCh-9 P-48PCh-9 P-49PCh-9 P-50PCh-9 P-51PCh-9 P-52PCh-9 P-53PCh-9 P-54PCh-9 P-55PCh-9 P-56PCh-9 P-57PCh-9 P-58PCh-9 P-59PCh-9 P-60PCh-9 P-61PCh-9 P-62PCh-9 P-63PCh-9 P-64PCh-9 P-65PCh-9 P-66PCh-9 P-67PCh-9 P-68PCh-9 P-69PCh-9 P-70PCh-9 P-71PCh-9 P-72PCh-9 P-73PCh-9 P-74PCh-9 P-75PCh-9 P-76PCh-9 P-77APCh-9 P-78APCh-9 P-79APCh-9 P-80APCh-9 P-81APCh-9 P-82APCh-9 P-83APCh-9 P-84APCh-9 P-85APCh-9 P-86APCh-9 P-87APCh-9 P-88APCh-9 P-89APCh-9 P-90APCh-9 P-91AP

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