Chapter 9, Problem 78AP

### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

Chapter
Section

### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
5 views

# For each of the following balanced equations, indicate how many moles of the product could be produced by complete reaction of 1.00 g of the reactant indicated in boldface. Indicate clearly the mole ratio used for the conversion.msp;  NH 3 ( g ) + HCl ( g ) → NH 4 Cl ( s ) msp;  CaO ( s ) + CO 2 ( g ) → CaCO 3 ( s ) msp;  4 Na ( s ) + O 2 ( g ) → 2 Na 2 O ( s ) msp;  2 P ( s ) + 3 Cl 2 ( g ) → 2 PCl 3 ( l )

Interpretation Introduction

(a)

Interpretation:

To calculate the moles of each product in the given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Explanation

The limiting reactant in a particular reaction has due to following properties:

1. Limiting reactant completely reacted in a particular reaction.
2. Limiting reactant determines the amount of the product in mole.

If any reactant left after competitions of reaction, thus it is said to excess reactant.

The balance chemical equation is as follows:

NH3(g)+HCl(g)  NH4Cl(s)

Given:

Amount of NH3 = 1.00 g

Number of moles=mass in gmolarmass=1

Interpretation Introduction

(b)

Interpretation:

To calculate the moles of each product in the given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(c)

Interpretation:

To calculate the moles of each product in the given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(d)

Interpretation:

To calculate the moles of each product in the given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

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