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ChemistryIntroductory Chemistry: A Foundation9th Edition

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Chapter 9, Problem 87AP
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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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The gaseous hydrocarbon acetylene, C 2 H 2 , is used in welders’ torches because of the large amount of heat released when acetylene burns with oxygen.

:math> 2 C 2 H 2 ( g ) + 5 O 2 ( g ) → 4 CO 2 ( g ) + 2 H 2 O ( g )

w many grams of oxygen gas are needed for the complete combustion of 150 g of acetylene?

Interpretation Introduction

Interpretation:

The mass of oxygen gas required for complete combustion of acetylene should be determined.

Concept Introduction:

The complete combustion of acetylene is represented as follows:

2C2H2(g)+5O2(g)→4CO2(aq)+2H2O(g)

The mass of oxygen required for complete combustion can be calculated from its number of moles and the number of moles required will depends on the number of moles of acetylene react in the chemical reaction.

Explanation

2C2H2(g)+5O2(g)→4CO2(aq)+2H2O(g)

From the above balanced chemical reaction, 2 mole of acetylene reacts with 5 moles of O2 to form 4 moles of CO2 and 2 moles of H2O.

The mass of acetylene is given 150 g, number of moles of acetylene can be calculated as follows:

n=mM

Here, m is mass and M is molar mass.

Molar mass of acetylene is 26.04 g/mol, number of moles will be:

n=150 g26.04 g/mol=5

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Sect-9.2 P-9.1SCSect-9.3 P-9.2SCSect-9.3 P-9.3SCSect-9.3 P-1CTSect-9.3 P-9.4SCSect-9.3 P-9.5SCSect-9.5 P-9.6SCSect-9.6 P-9.7SCCh-9 P-1ALQCh-9 P-2ALQ
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