   Chapter 9, Problem 89AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
7 views

# For each of the following unbalanced chemical equations, suppose 25.0 g of each reactant is taken. Show by calculation which reactant is limiting. Calculate the theoretical yield in grams of the product in boldface.msp;  C 2 H 5 OH ( l ) + O 2 ( g ) → CO 2 ( g ) + H 2 O ( l ) msp;  N 2 ( g ) + O 2 ( g ) → NO ( g ) msp;  NaClO 2 ( a q ) + Cl 2 ( g ) → NaCl ( a q ) msp;  H 2 ( g ) + N 2 ( g ) → NH 3 ( g )

Interpretation Introduction

(a)

Interpretation:

To determine the limiting and calculate the theoretical yield of product in given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Explanation

The limiting reactant in a particular reaction has due to following properties:

1. Limiting reactant completely reacted in a particular reaction.
2. Limiting reactant determines the amount of the product in mole.

If any reactant left after competitions of reaction, thus it is said to excess reactant.

The balance chemical equation is as follows:

C2H5OH(l) + 3O2(g)Δ 2CO2(g) + 3 H2O(g)

Given:

Amount of C2H5OH = 25.0 g

Amount of O2 = 25.0 g

Calculation:

Number of moles of C2H5OH and O2 calculated as follows:

Number of moles=mass in gmolarmass=25.0 g46.07 g/mol=0.542 moles C2H5OHNumber of moles=mass in gmolarmass=25

Interpretation Introduction

(b)

Interpretation:

To determine the limiting and calculate the theoretical yield of product in given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(c)

Interpretation:

To determine the limiting and calculate the theoretical yield of product in given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

Interpretation Introduction

(d)

Interpretation:

To determine the limiting and calculate the theoretical yield of product in given reaction

Concept Introduction:

A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.

Mass of any substance can be calculated as follows:

Mass in gram = Number of moles×Molar mass

Number of moles can be calculated as follows;

Number of moles=mass in gmolarmass.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 