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The properties of the plane region are
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International Edition---engineering Mechanics: Statics, 4th Edition
- A circular region of radius R/2 is cut out from the circular region of radius R as shown. For what distance d will kx for the new region be the same as kx (for the region before the cutout was removed?arrow_forwardThree forces intersect at point (1, 1, 1). Their magnitude and respective second point of incidence are as follows: 450 lbs (4, -3, 7), 600lbs (-1, 5, -4), 300lbs (-3, 6, -2) 1. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 2. Compute the direction cosine on the y-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513 3. Compute the direction cosine on the x-axis. a. 0.394 b. 0.124 c. 0.762 d. 0. 513arrow_forwardFind the x-component a force, 100N, acting 60 degrees below the x-axis,arrow_forward
- As shown, a member is fixed at the origin, point O, and has two applied forces, F1 and F2 , applied at the free end, point B. (Figure 3) The forces are given by F1=115 N i−150 N j+65 N k and F2 has magnitude 185 N and direction angles \alpha =142.0∘ , \beta =70.0∘ , and \gamma =59.2∘ . The dimensions are x1 = 1.40 m , y1 = 1.85 m , and z1 = 1.10 m . What is the moment about the origin due to the applied forces? Express the individual components of the Cartesian vector to three significant figures, separated by commas.arrow_forwardConsider the image below: A horizontal beam of length 8 m is pinned at its left end so that it is free to rotate about that end. It has a nonuniform linear mass density given by λ(x) = 78 x (kg/m). Its right end is secured by a rope, the angle shown being 45 degrees. Calculate the magnitude of the tension in the rope, in N. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forwardIt is common to hang objects on doorknobs and over-the-door hooks. There is a limit to the amount of weight that a door can hold because of the forces exerted on the hinges. A door of height h = 2.5 m and width h/2 has a mass of M = 36 kg. The mass is distributed uniformly, so the center of mass is located at the geometric center of the door. One hinge is located a distance h/4 from the top of the door. The second hinge is a distance h/4 from the bottom of the door. Refer to (a) in the figure. The door’s weight is supported entirely by the two hinges and each hinge supports half of the weight. In other words, the vertical force exerted by each hinge is exactly one half of the total weight, including any additional load. For this problem, take the positive y-direction to be directly upward and the positive x-direction pointing from the hinge side of the door to the knob side. 1.) calculate the force, with its sign in Newtons that the upper hinge exerts on the door in the x axis.…arrow_forward
- use the value w=2, x=0, y=2, z=8arrow_forwardDetermine the algebraic sum of the moments of forces relative to a point in F = 10.0 N; m =9.0 Nm, q =8.0 N/marrow_forward2 - Constant thickness homogeneous planar plate in the figure coordinates of the center of gravity M (Xm, Ym) of the surface area, Find it on the (x, y) set. t = 3 cm and a = 9 cm. Find the coordinates (Xm; Ym) of the rectangle extracted from this planar plate in the x and y axes.A) (9; 25.5)B) (9; 13)C) (9; 18)D) (9; 15)E) (9; 22.5)arrow_forward
- The system of converging forces is shown in the figure belowarrow_forward1. Vector 1 is 30 m/s at 300° and Vector 2 is 80 m/s at 50°. Direction at CCW due East.a) Calculate the resultant vector using Pythagorean theorem and/or trigonometry.arrow_forwardFor the vectors A = 8.0m South and B = 15.0 m, 300 E of N, use the method of components to find the magnitude and direction of the vector difference A – B.arrow_forward
- International Edition---engineering Mechanics: St...Mechanical EngineeringISBN:9781305501607Author:Andrew Pytel And Jaan KiusalaasPublisher:CENGAGE L