Basic Chemistry, Books a la Carte Edition (5th Edition)
Basic Chemistry, Books a la Carte Edition (5th Edition)
5th Edition
ISBN: 9780134177090
Author: Timberlake, Karen C.
Publisher: Prentice Hall
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Question
Chapter 9, Problem 9.45FU

(a)

Interpretation Introduction

Interpretation: The mass of C11H7O2Cl form from 2.2×102 kg of naphthol should be calculated.

Concept Introduction: The number of moles is calculated using the formula:

  number of moles = given massMolar Mass

(a)

Expert Solution
Check Mark

Answer to Problem 9.45FU

  2.2×102 kg of naphthol forms  315.3 kg of C11H7O2Cl .

Explanation of Solution

Given:

Mass of naphthol = 2.2 x 102 kg

Molar mass of naphthol = 144.17 g/mol

Equality:

1 kg = 1000 g

1 mole napthol = 144.17 g

1 mole napthol = 1 mole C11H7O2Cl

1 mole C11H7O2Cl = 206.62 g C11H7O2Cl

  2.2 x 102 kg x 1000 g1 kg x 1 mole napthol144.17 g naptholx1 mole C11H7O2Cl1 mole naptholx206.62 g C11H7O2Cl1 mol C11H7O2Clx1kg1000 g = 315.3 kg

(b)

Interpretation Introduction

Interpretation: The theoretical yield of C11H7O2Cl should be calculated.

Concept Introduction: The number of moles is calculated using the formula:

  number of moles = given massMolar Mass

(b)

Expert Solution
Check Mark

Answer to Problem 9.45FU

The theoretical yield of C11H7O2Cl is  143.4 g .

Explanation of Solution

Given:

Mass of napthol = 100 g

Molar mass of napthol = 144.17 g/mol

Mass of phosgene = 100 g

Molar mass of phosgene = 98.92 g/mol

Equality:

1 mole of phosgene = 98.92 g of phosgene

1 mole napthol = 144.17 g of napthol

Convert mass to moles;

  100 g phosgene x 1molephosgene98.92 g of phosgene= 1.01 mole

  100 g napthol x 1mole napthol144.17 g of napthol= 0.694 mole

The molar ratio of naphthol and phosgene is 1:1 thus, limiting reagent can be determined by just seeing the moles of both reactants.

Since moles of napthol are less so it must be limiting reagent and will determine the amount of product.

1 mole napthol = 1 mole C11H7O2Cl

1 mole C11H7O2Cl = 206.62 g C11H7O2Cl

Hence 0.694 moles napthol x 1mole C11H7O2Cl1 mole napthol x206.62 g C11H7O2Cl1 mole C11H7O2Cl= 143.4 g C11H7O2Cl

(c)

Interpretation Introduction

Interpretation: The percent yield should be calculated if the actual yield of C11H7O2Cl is 115 g.

Concept Introduction: The actual yield of the product is the amount of product which is formed at the end of reaction experimentally whereas theoretical yield represents the amount of product calculated by expecting that 100 % of reactant changes to product. The percent yield can be shown as:

  Percent yield = Actual yieldTheoretical yield x 100

(c)

Expert Solution
Check Mark

Answer to Problem 9.45FU

The percent yield of C11H7O2Cl is 80.2 %.

Explanation of Solution

Given:

Actual yield of C11H7O2Cl = 115 g

Theoretical yield = 143.4 g

  Percent yield = Actual yieldTheoretical yield x 100

Plug the values;

  Percent yield = 115 g143.4 g x 100 = 80.2 %

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Chapter 9 Solutions

Basic Chemistry, Books a la Carte Edition (5th Edition)

Ch. 9.3 - Sodium reacts with oxygen to produce sodium oxide....Ch. 9.3 - Nitrogen gas reacts with hydrogen gas to produce...Ch. 9.3 - Prob. 9.13QAPCh. 9.3 - lron (III) oxide reacts with carbon to give iron...Ch. 9.3 - Nitrogen dioxide and water react to produce nitric...Ch. 9.3 - Calcium cyanamide, CaCN2 , reacts with water to...Ch. 9.3 - When solid lead(II) sulfide reacts with oxygen...Ch. 9.3 - When the gases dihydrogen sulfide and oxygen...Ch. 9.4 - Prob. 9.19QAPCh. 9.4 - A clock maker has 15 clock faces. Each clock...Ch. 9.4 - Prob. 9.21QAPCh. 9.4 - Prob. 9.22QAPCh. 9.4 - 9.23 For each of the following reactions, 20.0 g...Ch. 9.4 - For each of the following reactions. 20.0 g of...Ch. 9.4 - Prob. 9.25QAPCh. 9.4 - Prob. 9.26QAPCh. 9.5 - 9.27 Carbon disulfide is produced by the reaction...Ch. 9.5 - Prob. 9.28QAPCh. 9.5 - Prob. 9.29QAPCh. 9.5 - Prob. 9.30QAPCh. 9.5 - Prob. 9.31QAPCh. 9.5 - Prob. 9.32QAPCh. 9.6 - In an exothermic reaction, is the energy of the...Ch. 9.6 - Prob. 9.34QAPCh. 9.6 - Prob. 9.35QAPCh. 9.6 - Classify each of the following as exothermic or...Ch. 9.6 - Prob. 9.37QAPCh. 9.6 - Prob. 9.38QAPCh. 9.6 - Prob. 9.39QAPCh. 9.6 - Prob. 9.40QAPCh. 9.6 - Prob. 9.41QAPCh. 9.6 - Calculate the enthalpy change for the reaction...Ch. 9.6 - Prob. 9.43QAPCh. 9.6 - Prob. 9.44QAPCh. 9 - Prob. 9.45FUCh. 9 - Prob. 9.46FUCh. 9 - Prob. 9.47UTCCh. 9 - Prob. 9.48UTCCh. 9 - Prob. 9.49UTCCh. 9 - Prob. 9.50UTCCh. 9 - Prob. 9.51UTCCh. 9 - If green spheres represent chlorine atoms and red...Ch. 9 - Prob. 9.53UTCCh. 9 - Prob. 9.54UTCCh. 9 - When ammonia NH3 reacts with fluorine F2 , the...Ch. 9 - Gasohol is a fuel that contains ethanol C2H6O that...Ch. 9 - When hydrogen peroxide H2O2 is used in rocket...Ch. 9 - Propane gas, C3H8 , reacts with oxygen to produce...Ch. 9 - When 12.8 g of Na and 10.2 g of Cl2 react, what is...Ch. 9 - If 35.8 g of CH4 and 75.5 g of S react, how many...Ch. 9 - Pentane gas, C5H12 , reacts with oxygen to produce...Ch. 9 - When nitrogen dioxide NO2 from car exhaust...Ch. 9 - The gaseous hydrocarbon acetylene, C2H2 , used in...Ch. 9 - The equation for the decomposition of potassium...Ch. 9 - When 28.0 g of acetylene reacts with hydrogen....Ch. 9 - When 50.0 g of iron(III) oxide reacts with carbon...Ch. 9 - Nitrogen and hydrogen combine to form ammonia....Ch. 9 - Prob. 9.68AQAPCh. 9 - The equation for the reaction of nitrogen and...Ch. 9 - The equation for the reaction of iron and oxygen...Ch. 9 - Each of the following is a reaction that occurs in...Ch. 9 - Each of the following is a reaction that occurs in...Ch. 9 - Prob. 9.73CQCh. 9 - Prob. 9.74CQCh. 9 - Prob. 9.75CQCh. 9 - Prob. 9.76CQCh. 9 - Prob. 9.77CQCh. 9 - Prob. 9.78CQCh. 9 - Prob. 9.79CQCh. 9 - Prob. 9.80CQCh. 9 - Prob. 9.81CQCh. 9 - Prob. 9.82CQ
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