Chapter 9, Problem 9.45QP

(a)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{H}}_{\text{2}}\text{S}$ is $\text{-2}$.

Explanation of Solution

The oxidation number of Sulfur in ${\text{H}}_{\text{2}}\text{S}$

• In ${\text{H}}_{\text{2}}\text{S}$ there is one Sulfur, two Hydrogen atoms.  The sum of oxidation numbers in a compound has to zero.  The oxidation number of Sulfur in ${\text{H}}_{\text{2}}\text{S}$.

  $\begin{array}{l}\text{2(1+)+(X)=0}\\ \text{(2+)+(x)=0}\\ \text{X =}-2\end{array}$

• The oxidation number of Sulfur in ${\text{H}}_{\text{2}}\text{S}$ is $\text{-2}$.

(b)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{S}}_{\text{8}}$ is $\text{0}$.

Explanation of Solution

The oxidation number of Sulfur in ${\text{S}}_{\text{8}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In ${\text{S}}_{\text{8}}$ is an element form of Sulfur so the sulfur is having zero oxidation state.
• The oxidation number of Sulfur in ${\text{S}}_{\text{8}}$ is $\text{0}$.

(c)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is $\text{+6}$.

Explanation of Solution

The oxidation number of Sulfur in ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ there is one Sulfur, 2 Hydrogen and 4 Oxygen atoms.  The sum of oxidation numbers in a compound has to zero.  The oxidation number of Sulfur in ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$.

  $\begin{array}{l}\text{2(1+)+(X)+4(-2)=0}\\ \text{(2+)+(X)+(-8)}\text{=0}\\ \text{X = +6}\end{array}$

• The oxidation number of Sulfur in ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ is $\text{+6}$.

(d)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{S}}^{\text{2-}}$ is $\text{-2}$.

Explanation of Solution

The oxidation number of Sulfur in ${\text{S}}^{\text{2-}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In the ${\text{S}}^{\text{2-}}$ is having one Sulfur having $\text{-2}$ charge so the oxidation number all so $\text{-2}$

(e)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{HS}}^{\text{-}}$ is $\text{-2}$.

Explanation of Solution

The oxidation number of Sulfur in ${\text{HS}}^{\text{-}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In ${\text{HS}}^{\text{-}}$ there is one Sulfur, one Hydrogen atoms.  The sum of oxidation numbers in a compound has to zero.  The oxidation number of Sulfur in ${\text{HS}}^{\text{-}}$.

  $\begin{array}{l}\text{1(1+)+(X) = -1}\\ \text{X}\text{=-2}\end{array}$

• The oxidation number of Sulfur in ${\text{HS}}^{\text{-}}$ is $\text{-2}$.

(f)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{SO}}_{\text{2}}$ is $\text{+4}$.

Explanation of Solution

To indicate the oxidation number of Sulfur in ${\text{SO}}_{\text{2}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In ${\text{SO}}_{\text{2}}$ there is 1 Sulfur and 2 Oxygen atoms.  The sum of oxidation numbers in a compound has to zero.  The oxidation number of Sulfur in ${\text{SO}}_{\text{2}}$.

$\begin{array}{l}\text{(X)+2(-2)=0}\\ \text{(X)+(-4)}\text{=0}\\ \text{X =}4\end{array}$

• The oxidation number of Sulfur in ${\text{SO}}_{\text{2}}$ is $\text{+4}$.

(g)

Interpretation Introduction

Interpretation:

The oxidation number of Sulfur in given species are should be arranged in the increasing order.

Concept introduction:

Oxidation number:

• The oxidation number of an atom is varied by involving in reaction is called redox reaction.
• In the redox reaction the number of electron is loosed or gained by an atom to form an electrically neutral product is called oxidation number.
• The sum of oxidation numbers of all the atoms present in the molecule is zero.
• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• The in the oxidation number of an atom in the element form is zero.

Answer to Problem 9.45QP

The oxidation number of Sulfur atom in given Oxoacids are,

The oxidation number of Sulfur in ${\text{SO}}_{\text{3}}$ is $\text{+6}$.

• The increasing order of oxidation number of Sulfur in given species is,

${\text{H}}_{\text{2}}{\text{S (-2),S}}^{\text{2-}}{\text{ (-2),HS}}^{\text{-}}\text{(-2)}\text{<}{\text{S}}_{\text{8}}{\text{(0) < SO}}_{\text{2}}\text{(+4) <}{\text{SO}}_{\text{3}}{\text{(+6),H}}_{\text{2}}{\text{SO}}_{\text{4}}\text{(+6)}$

Explanation of Solution

The oxidation number of Sulfur in ${\text{SO}}_{\text{3}}$

• The sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation number for oxygen is −2 and hydrogen is +1.
• In ${\text{SO}}_{\text{3}}$ is having 1 Sulfur and 3 Oxygen atoms.  The sum of oxidation numbers in a compound has to zero. The oxidation number of Sulfur in ${\text{SO}}_{\text{3}}$.

$\begin{array}{l}\text{(X)+3(-2)=0}\\ \text{(X)+(-6)}\text{=0}\\ \text{X =}6\end{array}$

• The oxidation number of Sulfur in ${\text{SO}}_{\text{3}}$ is $\text{+6}$.
• The above oxidation numbers are arranged to lowest to highest to give the increasing order Sulfur in given species.
• The increasing order of oxidation numbers of Sulfur in given species is,

• ${\text{H}}_{\text{2}}{\text{S (-2),S}}^{\text{2-}}{\text{ (-2),HS}}^{\text{-}}\text{(-2)}\text{<}{\text{S}}_{\text{8}}{\text{(0) < SO}}_{\text{2}}\text{(+4) <}{\text{SO}}_{\text{3}}{\text{(+6),H}}_{\text{2}}{\text{SO}}_{\text{4}}\text{(+6)}$