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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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Consider the following unbalanced chemical equation.

:math> LiOH ( s ) + CO 2 ( g ) Li 2 CO 3 ( s ) + H 2 O ( l )

67.4 g of lithium hydroxide reacts with excess carbon dioxide, what mass of lithium carbonate will be produced?

Interpretation Introduction

Interpretation:

The mass of lithium carbonate produced should be calculated.

Concept Introduction:

The expected or theoretical yield of the product depends on the limiting reactant of the reaction. Limiting reactant is the reactant that limits the mass of product formed in the reaction. The reactant other than limiting reactant is known as excess reactant.

Explanation

The mass of lithium hydroxide is 67.4 g and carbon dioxide present in excess.

Thus, amount of lithium carbonate produced depends on the amount of lithium hydroxide.

Calculate number of moles of lithium hydroxide as follows:

n=mM

Here, m is mass and M is molar mass

Molar mass of lithium hydroxide is 23.95 g/mol thus, number of moles of lithium hydroxide will be:

n=67.4 g23.95 g/mol=2.814 mol

From the balanced chemical reaction,

2LiOH(s)+CO2(g)Li2CO

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