Question
Book Icon
Chapter 9, Problem 9.71UTC
Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer
Check Mark

Answer to Problem 9.71UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

  1. Given: a polar solute and a polar solvent
  2. Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

  3. Given: a non-polar solute and a polar solvent
  4. Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

  5. Given: a non-polar solute and a non-polar solvent
  6. Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

Chemistry: An Introduction to General, Organic, and Biological Chemistry, Books a la Carte Edition & Modified MasteringChemistry with Pearson eText -- ValuePack Access Card Package, Chapter 9, Problem 9.71UTC

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 9 Solutions

Chemistry: An Introduction to General, Organic, and Biological Chemistry, Books a la Carte Edition & Modified MasteringChemistry with Pearson eText -- ValuePack Access Card Package

Ch. 9.2 - Indicate whether aqueous solutions of each of the...Ch. 9.2 - Prob. 9.12QAPCh. 9.2 - Prob. 9.13QAPCh. 9.2 - Prob. 9.14QAPCh. 9.2 - Calculate the number of equivalents in each of the...Ch. 9.2 - Calculate the number of equivalents in each of the...Ch. 9.2 - Prob. 9.17QAPCh. 9.2 - Prob. 9.18QAPCh. 9.2 - Prob. 9.19QAPCh. 9.2 - Prob. 9.20QAPCh. 9.3 - Prob. 9.21QAPCh. 9.3 - Prob. 9.22QAPCh. 9.3 - Determine whether each of the following solutions...Ch. 9.3 - Determine whether each of the following solutions...Ch. 9.3 - A solution containing 80. g of KClin 200 g of H2O...Ch. 9.3 - A solution containing 80. g of NaNO3 in 75 g of...Ch. 9.3 - Explain the following observations More sugar...Ch. 9.3 - Explain the following observations: And open can...Ch. 9.3 - Prob. 9.29QAPCh. 9.3 - Prob. 9.30QAPCh. 9.4 - What is the difference between a 5.0% (m/m)...Ch. 9.4 - What is the difference between a 10.0% (v/v)...Ch. 9.4 - Calculate the mass percent (m/m) for the solute in...Ch. 9.4 - Calculate the mass percent (m/m) for the solute in...Ch. 9.4 - Calculate the mass/volume(m/v) percent for the...Ch. 9.4 - Calculate the mass/volume (m/v) percent for the...Ch. 9.4 - Calculate the grams or milliliters of solute...Ch. 9.4 - Calculate the grams or ml of solute needed to...Ch. 9.4 - A mouthwash contains 22.5% (v/v) alcohol.If the...Ch. 9.4 - A bottle of champagne is 11% (v/v) alcohol. If...Ch. 9.4 - A patient received 100 mL of a 20.0% (m/v)...Ch. 9.4 - A patient received 250 mL of a 4.0% (m/v) amino...Ch. 9.4 - A patient needs 100. g of glucose in the next 12...Ch. 9.4 - A patient received 2.0 g of NaCl in 8 h. How many...Ch. 9.4 - Prob. 9.45QAPCh. 9.4 - For each of the following solutions, calculate...Ch. 9.4 - Prob. 9.47QAPCh. 9.4 - Prob. 9.48QAPCh. 9.4 - Calculate the gram of solely needed to prepare...Ch. 9.4 - Calculate the gram of solute needed to prepare...Ch. 9.4 - For each of the following solutions, calculate...Ch. 9.4 - Prob. 9.52QAPCh. 9.5 - Prob. 9.53QAPCh. 9.5 - Prob. 9.54QAPCh. 9.5 - Prob. 9.55QAPCh. 9.5 - Prob. 9.56QAPCh. 9.5 - Determine the final volume, in milliliters, of...Ch. 9.5 - Prob. 9.58QAPCh. 9.5 - Prob. 9.59QAPCh. 9.5 - Prob. 9.60QAPCh. 9.6 - Prob. 9.61QAPCh. 9.6 - Identify each of the following as characteristics...Ch. 9.6 - A 10% (m/v) starch solution is separated form a 1%...Ch. 9.6 - A 0.1% (m/v) albumin solution is separated form a...Ch. 9.6 - Indicate the compartment (A or B) that will...Ch. 9.6 - Indicate the compartment (A or B) that will...Ch. 9.6 - Will a red blood cell undergo creation, hemolysis,...Ch. 9.6 - Will a red blood cell undergo creation, hemolysis,...Ch. 9.6 - Each of the following mixtures is placed in a...Ch. 9.6 - Prob. 9.70QAPCh. 9 - Prob. 9.71UTCCh. 9 - Prob. 9.72UTCCh. 9 - Prob. 9.73UTCCh. 9 - Whydo lettuces leaves in a salad with after a...Ch. 9 - Prob. 9.75UTCCh. 9 - Prob. 9.76UTCCh. 9 - Prob. 9.77UTCCh. 9 - Prob. 9.78UTCCh. 9 - Prob. 9.79AQAPCh. 9 - Prob. 9.80AQAPCh. 9 - Prob. 9.81AQAPCh. 9 - Prob. 9.82AQAPCh. 9 - Prob. 9.83AQAPCh. 9 - Prob. 9.84AQAPCh. 9 - Prob. 9.85AQAPCh. 9 - Prob. 9.86AQAPCh. 9 - Prob. 9.87AQAPCh. 9 - Prob. 9.88AQAPCh. 9 - Prob. 9.89AQAPCh. 9 - Prob. 9.90AQAPCh. 9 - Prob. 9.91AQAPCh. 9 - Prob. 9.92AQAPCh. 9 - Prob. 9.93AQAPCh. 9 - Prob. 9.94AQAPCh. 9 - Prob. 9.95AQAPCh. 9 - Prob. 9.96AQAPCh. 9 - Calculate the final concentration of the solution...Ch. 9 - Calculate the final concentration of the solution...Ch. 9 - Prob. 9.99AQAPCh. 9 - Prob. 9.100AQAPCh. 9 - Prob. 9.101AQAPCh. 9 - Prob. 9.102AQAPCh. 9 - Prob. 9.103AQAPCh. 9 - Prob. 9.104AQAPCh. 9 - Prob. 9.105CQCh. 9 - 9.114. In a laboratory experiment, a 15.0-sample...Ch. 9 - Prob. 9.107CQCh. 9 - Prob. 9.108CQCh. 9 - Prob. 9.109CQCh. 9 - Prob. 9.110CQCh. 9 - Prob. 9.111CQCh. 9 - Prob. 9.112CQCh. 9 - Prob. 13CICh. 9 - The active ingredient in Turns is calcium...Ch. 9 - Tamiflu (oseltamivir), C16H28N2O4, is an antiviral...Ch. 9 - The compound butyric acid gives rancid butter its...Ch. 9 - Methane is a major component of purified natural...Ch. 9 - Automobile exhaust is a major cause of air...Ch. 9 - Bleach is often added to a wash to remove stains...Ch. 9 - Prob. 20CI
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY