   Chapter 9.1, Problem 42E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# In Problems 41-44, graph each function with a graphing calculator and use it to predict the limit. Check your work either by using the table feature of the calculator or by finding the limit algebraically. lim x → 5 x 2 − 7 x + 10 x 2 − 10 x + 25

To determine

To graph: The function f(x)=x27x+10x210x+25 using a graphing calculator, and predict the limit, limx5x27x+10x210x+25. Also, check the limit.

Explanation

Given Information:

The function is f(x)=x27x+10x210x+25.

The limit is limx5x27x+10x210x+25.

Graph:

Consider the provided function,

f(x)=x27x+10x210x+25

Use the ti-83 graphing calculator to plot the graph.

Step 1: Open the ti-83 graphing calculator.

Step 2: Press the [Y=] key and enter the function in Y1, Y1=X27X+10X210X+25.

Step 3: Press the [WINDOW] key and adjust the values accordingly.

Window:

Xmin=10,Xmax=10,Xsc1=2Ymin=10,Ymax=10,Ysc1=1

Step 4: Press the [TRACE] key.

Consider the provided limit,

limx5x27x+10x210x+25

The limit from the left is represented by limx5f(x) and the limit from the right is represented by limx5+f(x).

The limxcf(x) will exist at c=5 when the limit from the left, that is, the values of f(c) but c<5, is equal to the limit from the right, that is, the values of f(c) but c>5.

limx5f(x)=

And,

limx5+f(x)=

Since,

limx5f(x)limx5+f(x)

And both are not defined.

Hence, the value of limx5x27x+10x210x+25 does not exist.

To check the value of the limit, solve for the value of the limit

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 