   Chapter 9.1, Problem 6SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 3-6, evaluate the expression. ( 0 − 2 ) 2 ( 1 12 ) + ( 1 − 2 ) 2 ( 2 12 ) + ( 2 − 2 ) 2 ( 6 12 ) + ( 3 − 2 ) 2 ( 2 12 ) + ( 4 − 2 ) 2 ( 1 12 )

To determine

To calculate: The value of the expression

(02)2(112)+(12)2(212)+(22)2(612)+(32)2(212)+(42)2(112).

Explanation

Given information:

The expression, (02)2(112)+(12)2(212)+(22)2(612)+(32)2(212)+(42)2(112).

Formula used:

Multiply fractions:

(ab)(cd)=acbd,b0,d0

Calculation:

Consider the expression,

(02)2(112)+(12)2(212)+(22)2(612)+(32)2(212)+(42)2(112)

Use formula, multiply fractions,

(ab)(cd)=acbd,b0,d0

Now, apply above formula for expression

(02)2(112)+(12)2(212)+(22)2(612)+(32)2(212

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