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Math
GeometryElementary Geometry for College Students6th Edition

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Chapter 9.4, Problem 45E
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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

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Problem 15E
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Problem 23E
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Problem 37E
Problem 38E
Problem 39E
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Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
Problem 47E
Problem 48E
Problem 49E
Problem 50E
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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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Suppose that a semicircular region with a vertical diameter of length 6 is rotated about that diameter. Determine the exact surface area and the exact volume of the resulting solid of revolution.

To determine

To find:

The surface area and volume of the solid.

Explanation

Approach:

A solid of revolution is obtained by rotating a plane region around a straight line lying on the same plane. The straight line is called the axis of revolution. It may be vertical, horizontal or oblique.

A sphere is a three dimensional solid figure, which is made up of all the points in space, which lie at a common distance, called the radius, from a fixed point called the center of the sphere. The surface area of a sphere S=4Ï€r2, where r is the radius of the sphere.

All solid bodies occupy space. The measure of occupied space is called the volume of the object. Volume of a sphere V=43Ï€r3.

Calculation:

Consider a semi circular region that is rotated about its vertical diameter. The resultant solid of revolution that is formed is a sphere, where diameter d=6.

Radius r=d2=62=3

Surface area of sphere S=4·π

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Chapter 9.4,
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