Chapter 9.5, Problem 13PPB

(a)

Interpretation Introduction

Interpretation:

The concentrations of given compounds are should be determined by using given concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}.$

Concept introduction:

Concentration of ion:

The electrolyte is chemical compound, which dissociates to produce the ions in aqueous solutions.

The concentrations of produced ions in aqueous solution are given by the multiplication of coefficient of the ion with concentration of solution.

$\text{Ionic concentrations}\text{=}\text{solution}\text{concentration}\times \text{Ionic}\text{coefficients}$

Answer to Problem 13PPB

The concentration of ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$= $\text{0}\text{.36}\text{M}$

Explanation of Solution

The balanced equation is,

${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}\to 2N{a}^{+}{}_{(aq)}+{\text{SO}}_{\text{4}}{{}^{2-}}_{(aq)}$

$\begin{array}{l}\text{1}\text{mole}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{in }{\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}\\ [{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]=}\text{0}\text{.36}\text{M}\\ \text{=}0.36\text{M}\end{array}$

• ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$ contains one $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ ion so the concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ is equal to the concentration of ${\text{Na}}_{\text{2}}{\text{SO}}_{\text{4}}$.

(b)

Interpretation Introduction

Interpretation:

The concentrations of given compounds are should be determined by using given concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}.$

Concept introduction:

Concentration of ion:

The electrolyte is chemical compound, which dissociates to produce the ions in aqueous solutions.

The concentrations of produced ions in aqueous solution are given by the multiplication of coefficient of the ion with concentration of solution.

$\text{Ionic concentrations}\text{=}\text{solution}\text{concentration}\times \text{Ionic}\text{coefficients}$

Answer to Problem 13PPB

The concentration of ${\text{MgSO}}_{\text{4}}$= $\text{0}\text{.36}\text{M}$

Explanation of Solution

The balanced equation is,

${\text{MgSO}}_{\text{4}}\to M{g}^{2+}{}_{(aq)}+{\text{SO}}_{\text{4}}{{}^{2-}}_{(aq)}$

$\begin{array}{l}\text{1}\text{mole}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{in }{\text{MgSO}}_{\text{4}}\\ [{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]=}\text{0}\text{.36}\text{M}\\ \text{=}0.36\text{M}\end{array}$

• ${\text{MgSO}}_{\text{4}}$ contains one $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ ion so the concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ is equal to the concentration of ${\text{MgSO}}_{\text{4}}$.

(c)

Interpretation Introduction

Interpretation:

The concentrations of given compounds are should be determined by using given concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}.$

Concept introduction:

Concentration of ion:

The electrolyte is chemical compound, which dissociates to produce the ions in aqueous solutions.

The concentrations of produced ions in aqueous solution are given by the multiplication of coefficient of the ion with concentration of solution.

$\text{Ionic concentrations}\text{=}\text{solution}\text{concentration}\times \text{Ionic}\text{coefficients}$

Answer to Problem 13PPB

The concentration of ${\text{Al}}_{\text{2}}{{\text{(SO}}_{\text{4}})}_3$= $\text{1}\text{.2}\text{M}$

Explanation of Solution

The balanced equation is,

${\text{Al}}_{\text{2}}{{\text{(SO}}_{\text{4}})}_3\to 2A{l}^{3+}{}_{(aq)}+3{\text{SO}}_{\text{4}}{{}^{2-}}_{(aq)}$

$\begin{array}{l}3\text{mole}{\text{SO}}_{\text{4}}{}^{\text{2-}}{\text{in Al}}_{\text{2}}{{\text{(SO}}_{\text{4}}}_{)}\\ [{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]=}\frac{\text{0}\text{.36}\text{M}}{3}\\ \text{=}0.12\text{M}\end{array}$

• ${\text{Al}}_{\text{2}}{{\text{(SO}}_{\text{4}})}_3$ contains three $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ ion so the concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}$ is divided by three to give concentration of ${\text{Al}}_{\text{2}}{{\text{(SO}}_{\text{4}})}_3$.

Conclusion

The concentrations of given compounds are given by using given concentration of $\text{[}{\text{SO}}_{\text{4}}{}^{\text{2-}}\text{]}.$