   Chapter 9.5, Problem 42E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# Revenue The revenue (in dollars) from the sale of x units of a product is given by R ( x ) = 3000 2 x + 2 + 80 x − 1500 Find the marginal revenue when 149 units are sold. Interpret your result.

To determine

To calculate: The marginal revenue if the revenue (in dollars) from the sale of x units of a product is given by R(x)=(3000)(2x+2)+80x1500 at 149 units.

Explanation

Given Information:

The provided equation is R(x)=(3000)(2x+2)+80x1500.

Formula Used:

As per the quotient rule, if two functions are given in the form f(x)g(x), then the derivative is given as:

ddx(fg)=fggfg2.

The marginal revenue can be determined by the first derivative of the equation.

If a function is a sum of many functions, then the derivative is as follows:

f(x)=f1(x)+f2(x).

Calculation:

Consider the provided equation R(x)=(3000)(2x+2)+80x1500.

In order to take out the revenue from the sale of the next unit, the following needs to be done,

The derivative of the second function is,

f2(x)=80xf2(x)=80dxdx=80

The derivative of the third function is,

f3(x)=1500f3(x)=ddx(1500)=0

The value of the first function is:

In the equation (3000)(2x+2), the value of,

f(x)=(3000)

And

g(x)=(2x+2)

Apply the quotient rule of the equation,

ddx(fg)=ddx(3000)(2x+2)ddx(2x+2)(3000)(2x+2)2

Evaluate the equation further,

ddx(fg)=(ddx(3000))

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 