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Math
Mathematical Applications for the Management, Life, and Social Sciences11th Edition

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Chapter 9.5, Problem 42E
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Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

Solutions

Chapter
Section
Problem 1CP
Problem 2CP
Problem 3CP
Problem 4CP
Problem 5CP
Problem 2E
Problem 1E
Problem 4E
Problem 3E
Problem 5E
Problem 6E
Problem 8E
Problem 7E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
Problem 14E
Problem 15E
Problem 16E
Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
Problem 47E
Problem 48E
Problem 49E
Problem 50E
Problem 51E
Problem 52E
Problem 53E
Problem 54E
Problem 55E
Problem 56E
BuyFindarrow_forward

Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

Revenue The revenue (in dollars) from the sale of x units of a product is given by

R ( x ) = 3000 2 x + 2 + 80 x − 1500

Find the marginal revenue when 149 units are sold. Interpret your result.

To determine

To calculate: The marginal revenue if the revenue (in dollars) from the sale of x units of a product is given by R(x)=(3000)(2x+2)+80x−1500 at 149 units.

Explanation

Given Information:

The provided equation is R(x)=(3000)(2x+2)+80x−1500.

Formula Used:

As per the quotient rule, if two functions are given in the form f(x)g(x), then the derivative is given as:

ddx(fg)=f′⋅g−g′⋅fg2.

The marginal revenue can be determined by the first derivative of the equation.

If a function is a sum of many functions, then the derivative is as follows:

f′(x)=f1′(x)+f2′(x).

Calculation:

Consider the provided equation R(x)=(3000)(2x+2)+80x−1500.

In order to take out the revenue from the sale of the next unit, the following needs to be done,

The derivative of the second function is,

f2(x)=80xf2′(x)=80dxdx=80

The derivative of the third function is,

f3(x)=1500f3′(x)=ddx(1500)=0

The value of the first function is:

In the equation (3000)(2x+2), the value of,

f(x)=(3000)

And

g(x)=(2x+2)

Apply the quotient rule of the equation,

ddx(fg)=ddx(3000)⋅(2x+2)−ddx(2x+2)⋅(3000)(2x+2)2

Evaluate the equation further,

ddx(fg)=(ddx(3000))

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Sect-9.1 P-1CPSect-9.1 P-2CPSect-9.1 P-3CPSect-9.1 P-4CPSect-9.1 P-5CPSect-9.1 P-6CPSect-9.1 P-7CPSect-9.1 P-8CPSect-9.1 P-9CPSect-9.1 P-10CP
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Finding Partial Derivatives In Exercises 11-40, find both first partial derivatives. f(x,y)=4x3y2

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The quarterly sales data (number of copies sold) for a college textbook over the past three years follow. a. Co...

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Method of Variation of Parameters In Exercises 51-54, solve the differential equation by the method of variatio...

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Explain how sample size and sample variance influence the outcome of a hypothesis test and why a measure of eff...

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Describe how between-subjects designs are used to compare means and proportions for two or more groups, identif...

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