   # What is the energy of a photon with a wavelength of 58.4 nm in kilojoules/mole? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 9.A, Problem 2Q
Textbook Problem
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## What is the energy of a photon with a wavelength of 58.4 nm in kilojoules/mole?

Interpretation Introduction

Interpretation:

The energy of photon with the given wavelength of 58.4nm in kJ/mol has to be determined.

Concept Introduction:

Photoelectron spectroscopy: This is to energy measurement of electrons emitted from solids, gases or liquids by the photoelectric effect, in order to determine the binding energies of electrons in a substance.

The energy E of electromagnetic radiation is directly proportional to the frequency ν of the radiation.

Therefore,

E=hνE=hcλ

Where, E is the energy, h is the Plank’s constant (6.626×1034Js), ν is the frequency of radiation, c is the velocity of light and λ is the wavelength of the radiation.

1J=0.001kJ

### Explanation of Solution

The Helium (He) gas is the most common UV radiation source used for the photoelectron spectroscopy of molecules.  When electrical excited, He atoms emit nearly monochromic radiation at a wavelength of 58.4 nm.

The given photon has the wavelength of 58.4nm=58.4×10-9m thus the energy of corresponding photon can be determined as follows,

E=hνE=hcλ=6.63×10-34Js×3.0×108m/s58.4×10-9m=0

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