### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
Publisher: Cengage Learning
ISBN: 9781285195728

Chapter
Section

### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
Publisher: Cengage Learning
ISBN: 9781285195728
Chapter A, Problem 17PE
Textbook Problem
1 views

## For Problems 7-20, expand and simplify. ( x + 2 ) 7

To determine

To expand:

(x+2)7.

### Explanation of Solution

Let y=2.

The binomial expansion for (x+y)n is

xn+nxn1y+n(n1)2!.xn2y2+n(n1)(n2)3!xn3y3+........+yn

The exponents of x begin with the exponent of 7 and decrease term by term by 1 until the last term becomes 1, i.e. the exponent of x is 0.

The exponents of y begin with 0 and increase term by term by 1 until the last term contains the power of 7.

Therefore,

(x+2)7=x7+7x6(2)+762!x5(2)2+7653!x4(2)3+76544!x3(2)4+765435!x2(2)5+7654326!x(2)6+27

Here,

2!=213!=3214!=43215!=54321<

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