   # For Problems 7-20, expand and simplify. ( x + 3 ) 6 ### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
Publisher: Cengage Learning
ISBN: 9781285195728

#### Solutions

Chapter
Section ### Intermediate Algebra

10th Edition
Jerome E. Kaufmann + 1 other
Publisher: Cengage Learning
ISBN: 9781285195728
Chapter A, Problem 18PE
Textbook Problem
1 views

## For Problems 7-20, expand and simplify. ( x + 3 ) 6

To determine

To expand:

(x+3)6.

### Explanation of Solution

Let y=3.

The binomial expansion for (x+y)n is

xn+nxn1y+n(n1)2!.xn2y2+n(n1)(n2)3!xn3y3+........+yn

The exponents of x begin with the exponent of 6 and decrease term by term by 1 until the last term becomes 1, i.e. the exponent of x is 0.

The exponents of y begin with 0 and increase term by term by 1 until the last term contains the power of 6.

Therefore,

(x+3)6=x6+6x5(3)+652!x4(3)2+6543!x3(3)3+65434!x2(3)4+654325!x(3)5+36

Here,

2!=213!=3214!=432

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