# (a) Interpretation: The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined. Concept introduction: The minimum weight is calculated by the relative error formula which is given below- E r = E m − E t E t × 100 Here, E r = relative error E m = measured value E t = true value

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

#### Solutions

Chapter A1, Problem A1.4QAP
Interpretation Introduction

## (a)Interpretation:The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.Concept introduction:The minimum weight is calculated by the relative error formula which is given below-Er=Em−EtEt×100Here,Er = relative errorEm = measured valueEt = true value

Interpretation Introduction

### (b)Interpretation:The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.Concept introduction:The minimum weight is calculated by the relative error formula which is given below-Er=Em−EtEt×100Here,Er = relative errorEm = measured valueEt = true value

Interpretation Introduction

### (c)Interpretation:The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.Concept introduction:The minimum weight is calculated by the relative error formula which is given below-Er=Em−EtEt×100Here,Er = relative errorEm = measured valueEt = true value

Interpretation Introduction

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