# (a) Interpretation: The following data is obtained from the several food plant preparations for potassium ion- Samples precent K + 1 5.15,5.03,5.04,5.18,5.20 2 7.18,7.17,6.97 3 4.00,3.93,4.15,3.86 4 4.68,4.85,4.79,4.62 5 6.04,6.02,5.82,6.06,5.88 The value of mean and standard deviation for each sample is to be determined. Concept introduction: The following formula will be used- Mean- x ¯ = x 1 + x 2 + ......... + x n N Or x ¯ = ∑ i = 1 N x i N Deviation- s = ∑ i = 1 N x i 2 − ( ∑ i = 1 N x i ) 2 N N − 1

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

#### Solutions

Chapter A1, Problem A1.8QAP
Interpretation Introduction

## (a)Interpretation:The following data is obtained from the several food plant preparations for potassium ion- Samples precent K+ 1 5.15,5.03,5.04,5.18,5.20 2 7.18,7.17,6.97 3 4.00,3.93,4.15,3.86 4 4.68,4.85,4.79,4.62 5 6.04,6.02,5.82,6.06,5.88 The value of mean and standard deviation for each sample is to be determined.Concept introduction:The following formula will be used-Mean-x¯=x1+x2+.........+xnNOrx¯=∑i=1NxiNDeviation-s=∑i=1Nxi2−(∑i=1Nxi)2NN−1

Interpretation Introduction

### (b)Interpretation:The following data is obtained from the several food plant preparations for potassium ion- Samples precent K+ 1 5.15,5.03,5.04,5.18,5.20 2 7.18,7.17,6.97 3 4.00,3.93,4.15,3.86 4 4.68,4.85,4.79,4.62 5 6.04,6.02,5.82,6.06,5.88 The value s pooled, spooled is to be determined.Concept introduction:The following formula will be used-spooled=∑i=1N1(xi−x¯1)2+∑i=1N1(xi−x¯1)2+...N1+N2+....

Interpretation Introduction

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