(a) Interpretation: The table for the analysis of the six bottles of wine of same variety for residue sugar is given below- Bottle Percent (w/v) Residual sugar 1 0.99,0.84,1.02 2 1.02,1.13,1.17,1.02 3 1.25,1.32,1.13,1.20,1.12 4 0.72,0.77,0.61,0.58 5 0.90,0.92,0.73 6 0.70,0.88,0.72,0.73 The value of standard deviation for each set is to be determined. Concept introduction: The formula for the calculation of mean and standard deviation can be calculated as follows: x ¯ = x 1 + x 2 + ......... + x n N x ¯ = ∑ i = 1 N x i N s = ∑ i = 1 N x i 2 − ( ∑ i = 1 N x i ) 2 N N − 1

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Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213
BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

Solutions

Chapter A1, Problem A1.9QAP
Interpretation Introduction

(a)

Interpretation:

The table for the analysis of the six bottles of wine of same variety for residue sugar is given below-

Bottle Percent (w/v) Residual sugar
1 0.99,0.84,1.02
2 1.02,1.13,1.17,1.02
3 1.25,1.32,1.13,1.20,1.12
4 0.72,0.77,0.61,0.58
5 0.90,0.92,0.73
6 0.70,0.88,0.72,0.73

The value of standard deviation for each set is to be determined.

Concept introduction:

The formula for the calculation of mean and standard deviation can be calculated as follows:

x¯=x1+x2+.........+xnN

x¯=i=1NxiN

s=i=1Nxi2(i=1Nxi)2NN1

Interpretation Introduction

(b)

Interpretation:

The pooled data is to be determined for the absolute standard deviation for the given method.

Concept introduction:

The pooled value for the given data can be calculated using the following formula:

spooled=i=1N1(xix¯1)2+i=1N1(xix¯1)2+...N1+N2+....

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