Science

ChemistryPrinciples of Instrumental Analysis(a) Interpretation: The table for the analysis of the six bottles of wine of same variety for residue sugar is given below- Bottle Percent (w/v) Residual sugar 1 0.99,0.84,1.02 2 1.02,1.13,1.17,1.02 3 1.25,1.32,1.13,1.20,1.12 4 0.72,0.77,0.61,0.58 5 0.90,0.92,0.73 6 0.70,0.88,0.72,0.73 The value of standard deviation for each set is to be determined. Concept introduction: The formula for the calculation of mean and standard deviation can be calculated as follows: x ¯ = x 1 + x 2 + ......... + x n N x ¯ = ∑ i = 1 N x i N s = ∑ i = 1 N x i 2 − ( ∑ i = 1 N x i ) 2 N N − 1Start your trial now! First week only $4.99!*arrow_forward*

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7th Edition

Douglas A. Skoog + 2 others

Publisher: Cengage Learning

ISBN: 9781305577213

Chapter A1, Problem A1.9QAP

Interpretation Introduction

**(a)**

**Interpretation:**

The table for the analysis of the six bottles of wine of same variety for residue sugar is given below-

Bottle | Percent (w/v) Residual sugar |

1 | 0.99,0.84,1.02 |

2 | 1.02,1.13,1.17,1.02 |

3 | 1.25,1.32,1.13,1.20,1.12 |

4 | 0.72,0.77,0.61,0.58 |

5 | 0.90,0.92,0.73 |

6 | 0.70,0.88,0.72,0.73 |

The value of standard deviation for each set is to be determined.

**Concept introduction:**

The formula for the calculation of mean and standard deviation can be calculated as follows:

Interpretation Introduction

**(b)**

**Interpretation:**

The pooled data is to be determined for the absolute standard deviation for the given method.

**Concept introduction:**

The pooled value for the given data can be calculated using the following formula: