BuyFind

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343
BuyFind

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

Solutions

Chapter
Section
Chapter A.3, Problem 9E
Textbook Problem
3 views

Find the positive solution (or solutions) to the following equation:

1.80 x 2 + 0.850 x 9.50 = 0

Expert Solution
Interpretation Introduction

Interpretation:

The positive solution of the given equation has to be calculated.

Concept introduction:

Quadratic equation:

An equation involving only powers of x in which the highest power is 2. General form of this equation is given by

ax2+bx+c=0where,a,bandcareconstants.

The value of x is calculated by using the values of a,bandc

x=-b±b2-4ac2a

To find: The positive solution of the given equation

Answer to Problem 9E

The positive solution of the given equation is 2.0733.

Explanation of Solution

Given equation,

1.80x2+0.850x-9.50=0

Apply quadratic formula to find the value of x

1.80x2+0.850x-9.50=0here,a=1.80;b=0.850andc=-9.50x=-(0.850)±(0.850)2-4(1.80)(-9.50)2(1.80)=-0.850±0.7225+68.42(1.80)=-0.850±69.12253.6=-0.850±8.31403.6=2.0733and-2.5455

The positive solution for the given equation is 2.0733.

Conclusion

By using quadratic formula the positive solution of the given equation was calculated.

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Chapter A.3 Solutions

General Chemistry - Standalone book (MindTap Course List)

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