The value of to satisfy the following inequality equation:
The values of for the interval to satisfy eq. are and .
The unit circle with co-ordinates and radius to find out the values of for the interval :
Fig. Unit circle
From the unit circle figure:
The coordinate or sine value is equal to at and .
Sine value is less than or equal to in the first quadrant for the value of interval . Sine is between and , for the value of interval .
As in the entire fourth and third quadrant, the value is negative so, sine should be negative and it is less than for interval .
Therefore, the values of for the interval to satisfy eq. are and .
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