Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Question

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Answer 1

Question

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

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Answer 2

Question

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

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Answer 3

Question

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

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Answer 4

Question

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

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Answer 5

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

Answer 6

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

Answer 7

Chapter CSB1.1, Problem 1E

To determine

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Answer 8

Expert Solution & Answer

Answer to Problem 1E

The number 39 is divisible completely only by3.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information: The number is 39.

Calculation:

The ones digit of the number 39 is not divisible completely by 2. So, the number 39 is not divisible completely by 2.

The addition of the digits of the number 39 is 3. So, it is divisible completely by 3.

The ones digit of the number 39 is not 0 or 5. So, it is not divisible completely by 5.

The number 39 is divisible completely only by 3 but not 2. So, it is not divisible completely by 6.

The ones digit of the number 39 is not 0. So, it is not divisible completely by 10.

Therefore, the number 39 is divisible completely only by3.

Answer 12

Ch. CSB1.1 - Prob. 1E Ch. CSB1.1 - Prob. 2E Ch. CSB1.1 - Prob. 3E Ch. CSB1.1 - Prob. 4E Ch. CSB1.1 - Prob. 5E Ch. CSB1.1 - Prob. 6E Ch. CSB1.1 - Prob. 7E Ch. CSB1.1 - Prob. 8E Ch. CSB1.1 - Prob. 9E Ch. CSB1.1 - Prob. 10E

Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

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Whether the number 39 is divisible completely by 2, 3, 5, 6, or 10 by using divisibility rules.

Answer to Problem 1E

Explanation of Solution

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