Single Variable Calculus: Concepts and Contexts, Enhanced Edition
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
4th Edition
ISBN: 9781337687805
Author: James Stewart
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter T, Problem 1CDT

Chapter T, Problem 1CDT, FIGURE FOR PROBLEM 1 1. The graph of a function f is given at the left (a) State the value of f(1)

FIGURE FOR PROBLEM 1

1. The graph of a function f is given at the left

  1. (a) State the value of f(−1)
  2. (b) Estimate the value of f(2)
  3. (c) For what values of x is f(x) = 2?
  4. (d) Estimate the values of x such that f(x) = 0.
  5. (e) State the domain and range of f.

(a)

Expert Solution
Check Mark
To determine

To state: The value of f(1).

Answer to Problem 1CDT

The value of f(1) is 2.

Explanation of Solution

Spot the point (1,0) in the negative x-axis in the figure.

To find the value of f(1), go down through the straight line x=1 until the graph of the function is reached.

Now the intersecting point of the graph of the function and the line x=1 is the value of f(1).

From the figure, it is clear that the value of f(1) is 2.

Thus, the value of f(1) is 2.

(b)

Expert Solution
Check Mark
To determine

To estimate: The value of f(2).

Answer to Problem 1CDT

The value of f(2) is 2.8.

Explanation of Solution

Spot the point (2,0) in the positive x-axis in the figure.

To find the value of f(2), go down through the straight line x=2 until the graph of the function is reached.

Now the intersecting point of the graph of the function and the line x=2 is the value of f(2).

From the figure, it is clear that the value of f(2) is 2.8.

Thus, the value of f(2) is 2.8.

(c)

Expert Solution
Check Mark
To determine

To find: The value of x such that f(x)=2.

Answer to Problem 1CDT

The value of x is 3 and 1 such that f(x)=2.

Explanation of Solution

Spot the point (0,2) in the positive y-axis in the figure.

To find the value of x, go left and right through the straight line y=2 horizontally until the graph of the function is reached.

Now the x-coordinate of the intersecting point of the graph of the function and the line y=2 is the value of the required x.

From the figure, it is clear that the value of f(x)=2 is for x=3 and x=1.

Thus, the value of x is 3 and 1 such that f(x)=2.

(d)

Expert Solution
Check Mark
To determine

To estimate: The value of x such that f(x)=0.

Answer to Problem 1CDT

The value of x is 2.5 and 0.3 such that f(x)=0.

Explanation of Solution

Spot the point (0,0) in the positive y-axis in the figure.

To find the value of x, go left and right through the straight line y=0 horizontally until the graph of the function is reached.

Now the x-coordinate of the intersecting point of the graph of the function and the line y=0 is the value of the required x.

From the figure, it is clear that the value of f(x)=0 is for x=2.5 and x=0.3.

Thus, the value of x is 2.5 and 0.3 such that f(x)=0.

(e)

Expert Solution
Check Mark
To determine

To state: The domain and range of the function f(x).

Explanation of Solution

The set of all possible values of the independent variables in a function is called the domain of the function.

From the figure, it is clear that the function f(x) is defined on the interval [3,3].

Thus, the domain of the function f(x) is [3,3].

The resulting set of possible values of the dependent variable is called the range.

From the figure, it is clear that the function f(x) is attains its values in the interval [2,3].

Thus, the range of the function f(x) is [2,3].

Chapter T Solutions

Single Variable Calculus: Concepts and Contexts, Enhanced Edition

Knowledge Booster
Background pattern image
Calculus
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Text book image
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Text book image
Precalculus
Calculus
ISBN:9780135189405
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning
Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY