   Chapter T, Problem 3CDT ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# Find the domain of the function. (a) f ( x ) = 2 x + 1 x 2 + x − 2 (b) g ( x ) = x 3 x 2 + 1 (c) h ( x ) = 4 − x + x 2 − 1

(a)

To determine

To find: The domain of the function f(x)=2x+1x2+x2.

Explanation

Formula used:

Domain: The set of all possible values of the independent variables in a function is called the domain of the function.

Calculation:

Consider the given function f(x)=2x+1x2+x2.

The function is not defined if the denominator of the function equals to 0.

The denominator of the function f(x)=2x+1x2+x2 is x2+x2.

Thus,

x2+x2=0(x+2)(x1)=0

Therefore, the function f(x)=2x+

(b)

To determine

To find: The domain of the function g(x)=x3x2+1.

(c)

To determine

To find: The domain of the function h(x)=4x+x21.

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