Chemistry with Access Code, Hybrid Edition - 9th Edition - by Steven S. Zumdahl - ISBN 9781285188492

Chemistry with Access Code, Hybrid Edit...
9th Edition
Steven S. Zumdahl
Publisher: CENGAGE L
ISBN: 9781285188492

Solutions for Chemistry with Access Code, Hybrid Edition

Book Details

This fully updated Hybrid Edition of CHEMISTRY 9e emphasizes a thoughtful approach built on problem solving, and speaks directly to students about solving chemical problems- learning to think like chemists-so that they can apply the process of problem solving to their lives.

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We offer sample solutions for Chemistry with Access Code, Hybrid Edition homework problems. See examples below:

Chapter 1, Problem 63EChapter 1, Problem 64EChapter 1, Problem 73EChapter 1, Problem 113CPChapter 2, Problem 1RQChapter 2, Problem 64EChapter 2, Problem 67EChapter 2, Problem 68EExplanation: Atomic number given is 13. From the periodic table we can identify that the element...Chapter 2, Problem 71EExplanation: To determine: The naming of CuI The name of CuI is copper(I) iodide. In naming of...Explanation: To determine: The naming of HC2H3O2 The naming of HC2H3O2 is acetic acid. Rules for...To determine: The formula of of sulfur difluoride The formula of sulfur difluoride is SF2 Sulfur...Explanation: To determine: The formula of sodium oxide. The formula of sodium oxide is Na2O The...Chapter 2, Problem 86EChapter 2, Problem 88EExplanation: To determine: The formula and the name of the binary compound formed from Ca and N. The...Explanation: To determine: The explanation for the term “counting by weighing”. The stated concept,...Chapter 3, Problem 59EChapter 3, Problem 60EChapter 3, Problem 61EExplanation: Given The mass of P4O6 is 1.00 g . The molar mass of P4O6 is 219.866 g/mol . Formula...Chapter 3, Problem 64EChapter 3, Problem 67EChapter 3, Problem 68EChapter 3, Problem 71EChapter 3, Problem 73EChapter 3, Problem 76EChapter 3, Problem 79EChapter 3, Problem 100EChapter 3, Problem 109EChapter 3, Problem 119EChapter 3, Problem 121EChapter 3, Problem 124EChapter 3, Problem 150AEChapter 3, Problem 152CWPChapter 3, Problem 180IPChapter 4, Problem 1RQChapter 4, Problem 7RQExplanation: NaBr(s)→Na(aq)++Braq- Figure 1 Let us consider the above molecular-level pictures of...Explanation: Record the given data Moles of Sodium phosphate= 0.200 moles Volume of the solution=...Chapter 4, Problem 66EChapter 4, Problem 79EChapter 4, Problem 82EChapter 4, Problem 93AEChapter 4, Problem 121CPChapter 4, Problem 122CPChapter 4, Problem 123CPExplanation Record the given data Mass of the sample mixture = 0.205 g Mass of the precipitate =...Explanation: Given: Record the given data Upstream at which the stream rate flows = 5.00×104 L/s...Chapter 4, Problem 144MPChapter 4, Problem 145MPA barometer consists of Mercury column that is tipped inverted and positioned in a dish containing...Chapter 5, Problem 41EExplanation: The relation between pressures measured in the manometers containing mercury and...Explanation According to ideal gas equation, PV=nRT By rearranging the above equation, PVnT=R Since...Chapter 5, Problem 88EExplanation: To find: the mole fractions of CH4 and O2 in the given mixture if the partial pressure...Explanation To find: the number of moles of dimethyl hydrazine from its given mass. The number of...Explanation To determine: The partial pressure of carbon monoxide Partial pressure of carbon...Explanation To determine: The mixing ratio of benzene Mixing ratio of benzene = 9.47 × 10-3ppmv For...Explanation: The mass percent from the given data is, 26.1% Carbon13.1% Hydrogen61.0% Nitrogen Mass...Chapter 5, Problem 135AEExplanation To find: the empirical formula of the compound Convert the mass percent to gram 58.51%...Chapter 5, Problem 139AEChapter 5, Problem 152CPChapter 5, Problem 153CPExplanation To determine: Mass of hot air when the average molar mass of air 29.0g/mol Mass of hot...Chapter 5, Problem 162IPChapter 6, Problem 1RQChapter 6, Problem 20QChapter 6, Problem 34EChapter 6, Problem 50EChapter 6, Problem 52EChapter 6, Problem 79EChapter 6, Problem 80EExplanation: The balanced equation is: a) N2(g)→N2(l) In (a) the volume of products is decreases...Chapter 6, Problem 108AEChapter 6, Problem 115AEChapter 6, Problem 130CPChapter 6, Problem 131CPChapter 6, Problem 134IPChapter 6, Problem 135IPChapter 6, Problem 137MPChapter 7, Problem 1RQChapter 7, Problem 24QChapter 7, Problem 43EChapter 7, Problem 57EChapter 7, Problem 58EChapter 7, Problem 61EChapter 7, Problem 62EChapter 7, Problem 63EChapter 7, Problem 74EChapter 7, Problem 79EChapter 7, Problem 81EChapter 7, Problem 82EChapter 7, Problem 86EChapter 7, Problem 87EChapter 7, Problem 94EChapter 7, Problem 95EChapter 7, Problem 97EChapter 7, Problem 142AEChapter 7, Problem 171CPChapter 8, Problem 1RQExplanation: Refer to figure 3-4. The electro negativity of carbon (C) , nitrogen (N) , and oxygen...Explanation: Refer to figure 3-4 The electro negativity of Sodium (Na) Potassium (K) and Rubidium...Chapter 8, Problem 46EChapter 8, Problem 47EChapter 8, Problem 49EExplanation: In a periodic table the size of ions depends on the nuclear attraction on the valence...Chapter 8, Problem 54EChapter 8, Problem 62EChapter 8, Problem 81EChapter 8, Problem 84EChapter 8, Problem 89EChapter 8, Problem 101EChapter 8, Problem 102EChapter 8, Problem 129AEChapter 8, Problem 154CPChapter 8, Problem 155CPChapter 9, Problem 1RQChapter 9, Problem 23EChapter 9, Problem 24EChapter 9, Problem 26EChapter 9, Problem 29EChapter 9, Problem 30EChapter 9, Problem 39EChapter 9, Problem 52EChapter 9, Problem 53EChapter 9, Problem 63AEChapter 9, Problem 89CPChapter 10, Problem 1RQChapter 10, Problem 41EExplanation: CCl4 , CBr4, CF4 Identify the compound which has highest boiling point and justify it....Chapter 10, Problem 53EChapter 10, Problem 55EChapter 10, Problem 56EChapter 10, Problem 57EChapter 10, Problem 58EChapter 10, Problem 59EChapter 10, Problem 60EChapter 10, Problem 62EChapter 10, Problem 80EChapter 10, Problem 88EChapter 10, Problem 131CPChapter 10, Problem 146CPChapter 10, Problem 148IPExplanation: To explain molarity Molarity can be defined as moles of solute to litres of solution....Chapter 11, Problem 16SRChapter 11, Problem 31EExplanation: Record the given data Gram equivalent of HCl = 0.25 Molarity of HCl = 0.25 M To...Explanation: KrF2 8+2(7)=22e- KrF2 is dissolves in CCl4 . KrF2 is non-polar molecule that makes it...Chapter 11, Problem 55EChapter 11, Problem 79EExplanation: Record the given data, Molality of MgCl2= 0.050 m Molality of FeCl3= 0.050 m To...Explanation: Record the given data, Molality of MgCl2= 0.050 m Molality of FeCl3= 0.050 m To...Explanation: To find the Acetone and water polarity CH3COCH3 and H2O The electrostatic possible...Explanation: Record the given data, Freezing point of an aqueous solution =- 2.79°C To calculate...Mass of Sodium = 285-315 mg Mass of Potassium = 14.1-17.3 mg Mass of Calcium = 4.9-6.0 mg Mass of...Chapter 11, Problem 109AEChapter 11, Problem 120CPChapter 11, Problem 132IPChapter 12, Problem 1RQChapter 12, Problem 30EChapter 12, Problem 33EChapter 12, Problem 35EChapter 12, Problem 36EChapter 12, Problem 58EChapter 12, Problem 84AEChapter 12, Problem 86AEChapter 12, Problem 87AEChapter 12, Problem 91AEChapter 12, Problem 93AEChapter 12, Problem 105CPChapter 12, Problem 112CPChapter 13, Problem 1RQChapter 13, Problem 5ALQChapter 13, Problem 23EChapter 13, Problem 39EChapter 13, Problem 42EChapter 13, Problem 54EChapter 13, Problem 56EChapter 13, Problem 57EChapter 13, Problem 72AEChapter 13, Problem 73AEChapter 13, Problem 78AEChapter 13, Problem 104CPChapter 13, Problem 106CPChapter 14, Problem 1RQChapter 14, Problem 49EChapter 14, Problem 50EChapter 14, Problem 51EChapter 14, Problem 52EChapter 14, Problem 63EChapter 14, Problem 64EChapter 14, Problem 68EChapter 14, Problem 73EChapter 14, Problem 74EExplanation: To determine: The pH, [H+] and [OH−] of (C2H5)3N . The equilibrium constant expression...Chapter 14, Problem 101EChapter 14, Problem 107EChapter 14, Problem 108EChapter 14, Problem 109EChapter 14, Problem 119EChapter 14, Problem 120EChapter 14, Problem 123EChapter 14, Problem 126EChapter 14, Problem 151AEChapter 15, Problem 1RQChapter 15, Problem 7RQChapter 15, Problem 43EChapter 15, Problem 57EChapter 15, Problem 58EChapter 15, Problem 59EChapter 15, Problem 60EChapter 15, Problem 61EChapter 15, Problem 62EChapter 15, Problem 63EChapter 15, Problem 64EChapter 15, Problem 65EExplanation The value of pH of solution when 0.0 ​mL NaOH has been added is. 1.0_ . Given: The...Chapter 15, Problem 107CWPChapter 16, Problem 1RQExplanation To determine: The solubility product of CaC2O4 . The concentration of Ca2+ is 4.8×10−5...Chapter 16, Problem 22EChapter 16, Problem 27EChapter 16, Problem 28EChapter 16, Problem 35EChapter 16, Problem 36EChapter 16, Problem 37EChapter 16, Problem 40EChapter 16, Problem 53EChapter 16, Problem 70EChapter 16, Problem 102CPChapter 17, Problem 1RQChapter 17, Problem 53EChapter 17, Problem 54EChapter 17, Problem 63EChapter 17, Problem 64EChapter 17, Problem 68EChapter 17, Problem 70EChapter 17, Problem 72EChapter 17, Problem 74EChapter 17, Problem 78EChapter 17, Problem 86AEChapter 17, Problem 90AEChapter 17, Problem 119MPChapter 18, Problem 1RQChapter 18, Problem 16RORRExplanation: Given: I- (aq) + ClO- (aq) →I3− (aq) + Cl-(aq) To write the equations for two...Explanation: Given: Cu (s) + NO3- (aq) →Cu2+ (aq) + NO(g) To write the equations for two...Chapter 18, Problem 47EChapter 18, Problem 75EChapter 18, Problem 76EChapter 18, Problem 85EChapter 18, Problem 86EChapter 18, Problem 95EChapter 18, Problem 115AEChapter 18, Problem 117AEExplanation: Given The given reaction is, Fe(s)+HCl(aq)→HFeCl4(aq)+H2(g) . In this equation, the...Chapter 18, Problem 144CPExplanation The half cell reactions are, Anode: Hg→Hg2++2e− Eanodeο=0.242 V Cathode: 2Ag++2e−→2Ag...Chapter 18, Problem 153CPChapter 18, Problem 159MPExplanation (a) To define: The term thermodynamic stability. The thermodynamic stability is related...Explanation: Alpha particle is emitted. The parent nuclide is 232Th and the nuclide after the...Explanation The most stable isotope is 81Kr and the hottest one is 73Kr The nuclides having longer...Explanation Given The atomic mass of 232Pu is 3.85285×10−22 g . The mass of a neutron is...Explanation The atomic mass of 11H=1.0078 amu The mass of a neutron is 1.0087 amu . Mass of...Explanation Given The value of half life of 87Rb is 4.5×109 years . The decay constant is calculated...Explanation The decay constant is calculated by the formula given below. λ=0.693t1/2 Where t1/2 is...Explanation: The zirconium metal is capable of reducing water to form hydrogen gas at standard...Explanation The number of α and β particles produced are 4_ and 2_ . The mass number of 92238U is...Explanation The nuclear reaction for the synthesis of cobalt- 60 is, 2658Fe+201n→ 2760Co+ −10e . The...Chapter 20, Problem 1RQExplanation The valence electron configuration for halogens is ns2np5 . The common halogen elements...Explanation The value of ΔH° for the given reaction is 180 kJ_ . The stated reaction is,...Explanation: The compound XeO4 and IO4− ion are isoelectronic. The molecule xenon tetroxide (XeO4)...Explanation: The Lewis structure, molecular structure, bond angle and hybridization of central atom...Explanation Given Dimension of room is 10.0 m×10.0 m×10.0 m . Temperature is 25 °C . Pressure is...Explanation: Hydrogen gas is produced by reacting graphite with water. C(s)+H2O(g)→CO(g)+H2(g) The...Explanation: The number of moles of hydrogen gas is 0.249 mol_. Given Mass of alkaline earth metal...Explanation: Mass of radon (Ra) is 25 g_ . Given Mass of pitch-blende is 1.75×108 g . The conversion...Explanation Given Temperature is 900 K . Pressure of In(CH3)3 is 2.00 atm . Volume of In(CH3)3 is...Chapter 20, Problem 108IPChapter 20, Problem 109IPChapter 21, Problem 1RQExplanation: (I) To determine: The geometry and associated bond angles when a metal ion has a...Explanation: Atomic number of Nickel is 28 . Accordingly the electronic configuration is –...Explanation: Atomic number of Nickel is 22 . Accordingly the electronic configuration is –...EXPLANATION (a) To write: The electron configuration of metal ion in (NH4)2[Fe(H2O)2Cl4] . The...Explanation The complex ion is [Ru(NH3)5Cl]2+. This ion contains positive charge. Oxidation state of...Explanation The complex compound is [Co(NH3)6]Cl2 . Oxidation state of Chlorine ion (Cl−) is −1 ....Explanation The complex compound is [Cr(H2O)5Br]Br2 . Oxidation state of Bromine ion (Br−) is −1 ....Explanation The value of ΔH° for the given reaction is −11 kJ_ . For the reaction,...Explanation The reaction that takes place is, 3Fe2O3(s)+CO(g)→2Fe3O4(s)+CO2(g) Refer to Appendix 4....Explanation The given equations are, Co+3+e−→Co+2 Eο=1.82 V (1) Co2++3en→Co(en)32+ K=1.5×1012 (2)...Chapter 21, Problem 99IPChapter 22, Problem 1RQChapter 22, Problem 5RQExplanation: The type of isomerism that could be exhibited by C6H12 and an example that illustrates...Chapter 22, Problem 16EChapter 22, Problem 45EExplanation To determine: The monomer of the given polymer. The monomer is vinyl fluoride. It is an...Explanation The correct name of the compound is 2,3,5,6−Tetramethyl−octane whose structure is shown...Explanation The structure of the given compound 2,3,7,8−tetrachloro−dibenzo−p−dioxin is shown in...Chapter 22, Problem 130AEChapter 22, Problem 136AEExplanation The equilibrium constant for the given reaction is 6.88×10−13_ . The equilibrium...Chapter 22, Problem 148CPExplanation The structure of C5H12 is shown in Figure 1. The structure of C5H12 is, Figure 1 The...Explanation The structure of the polymer of ABS plastic is shown in figure 1. The reaction of Abs...Explanation Given Electronic configuration of M+2 is [Ar]3d10. So, atomic number of M is 30. In...Explanation The empirical formula of the given helicene is C5H3 . Helicene is an aromatic compound...The correct responses are urea and Ammonium cyanate. The first organic compound that is synthesized...Explanation Aldohexose is a six carbon aldehyde sugar with an aldehyde group on one end.

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