Physics for Scientists and Engineers, Technology Update, Hybrid Edition (with Enhanced WebAssign Multi-Term LOE Printed Access Card for Physics) - 9th Edition - by Raymond A. Serway, John W. Jewett - ISBN 9781305116429

Physics for Scientists and Engineers, T...
9th Edition
Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
ISBN: 9781305116429

Solutions for Physics for Scientists and Engineers, Technology Update, Hybrid Edition (with Enhanced WebAssign Multi-Term LOE Printed Access Card for Physics)

Book Details

Achieve success in your physics course by making the most of what PHYSICS FOR SCIENTISTS AND ENGINEERS has to offer. From a host of in-text features to a range of outstanding technology resources, you'll have everything you need to understand the natural forces and principles of physics. Throughout every chapter, the authors have built in a wide range of examples, exercises, and illustrations that willhelp you understand the laws of physics AND succeed in your course! This briefer, paperbound version does not contain the end-of-chapter problems, which can be accessed in Enhanced WebAssign, the online homework and learning system for this book. Access to Enhanced WebAssign and an eBook version is included with this Hybrid version. The eBook is the full version of the text, with all end-of-chapter questions and problem sets.

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We offer sample solutions for Physics for Scientists and Engineers, Technology Update, Hybrid Edition (with Enhanced WebAssign Multi-Term LOE Printed Access Card for Physics) homework problems. See examples below:

Chapter 1, Problem 1.73APChapter 2, Problem 2.2QQChapter 2, Problem 2.1PChapter 2, Problem 2.17PChapter 2, Problem 2.18PChapter 2, Problem 2.20PChapter 2, Problem 2.42PChapter 2, Problem 2.43PChapter 2, Problem 2.62APChapter 2, Problem 2.69APChapter 2, Problem 2.76APChapter 2, Problem 2.82CPChapter 2, Problem 2.83CPChapter 3, Problem 3.1QQGiven info: The value of two vector A→ and B→ is 3i^−2j^ and −i^−4j^ respectively. Write the...Chapter 3, Problem 3.26PChapter 3, Problem 3.40PChapter 3, Problem 3.43PChapter 3, Problem 3.46PChapter 3, Problem 3.54APChapter 3, Problem 3.56APChapter 3, Problem 3.61APChapter 3, Problem 3.67CPChapter 4, Problem 4.1QQChapter 4, Problem 4.1PChapter 4, Problem 4.4PChapter 4, Problem 4.5PChapter 4, Problem 4.8PChapter 4, Problem 4.29PChapter 4, Problem 4.56APChapter 4, Problem 4.61APChapter 4, Problem 4.65APChapter 4, Problem 4.72APChapter 4, Problem 4.73APChapter 4, Problem 4.77APChapter 5, Problem 5.1QQChapter 5, Problem 5.5PChapter 5, Problem 5.15PChapter 5, Problem 5.19PChapter 5, Problem 5.22PChapter 5, Problem 5.36PChapter 5, Problem 5.64PChapter 5, Problem 5.76APChapter 5, Problem 5.79APChapter 5, Problem 5.88APChapter 5, Problem 5.92APChapter 5, Problem 5.96CPChapter 5, Problem 5.98CPChapter 5, Problem 5.99CPChapter 5, Problem 5.103CPChapter 6, Problem 6.1QQChapter 6, Problem 6.10PChapter 6, Problem 6.18PChapter 6, Problem 6.34PChapter 6, Problem 6.47APFrom the Figure, the terminal speed of the filters is 5(m/s)2 and the resistive force towards the...Chapter 6, Problem 6.65CPChapter 6, Problem 6.67CPChapter 6, Problem 6.68CPGiven info: The expression of magnitude of resistive force exerted on a sphere is F=(arv+br2v2)...The Earth revolve around the sun in an orbit and the orbit is perfectly circular. Formula to...Given info: A 2 kg object falling from the 5 cm above the floor, a 2 kg object falling from the 120...Chapter 7, Problem 7.11PChapter 7, Problem 7.12PChapter 7, Problem 7.39PChapter 7, Problem 7.45PChapter 7, Problem 7.46PChapter 7, Problem 7.57APThe mass of an object is 5.00 kg, the magnitude of the first force is 25.0 N at an angle of 35.0°...Chapter 7, Problem 7.66CPChapter 7, Problem 7.67CPChapter 8, Problem 8.1QQChapter 8, Problem 8.25PChapter 8, Problem 8.41PChapter 8, Problem 8.49APChapter 8, Problem 8.61APChapter 8, Problem 8.62APChapter 8, Problem 8.65APChapter 8, Problem 8.77APChapter 8, Problem 8.80CPGiven info: The mass of Jane is 50.0 kg , magnitude of force is 110​ N , mass of Tarzan is 80.0 kg ,...Given info: The length of the string is 80.0 cm , mass of the ball is 300 g . The diagram is shown...Chapter 9, Problem 9.1QQChapter 9, Problem 9.3QQChapter 9, Problem 9.27PChapter 9, Problem 9.35PChapter 9, Problem 9.43PChapter 9, Problem 9.54PChapter 9, Problem 9.55PChapter 9, Problem 9.64PChapter 9, Problem 9.69APChapter 9, Problem 9.77APChapter 9, Problem 9.83APChapter 9, Problem 9.87APChapter 9, Problem 9.90APChapter 9, Problem 9.91APChapter 10, Problem 10.1QQChapter 10, Problem 10.19PChapter 10, Problem 10.26PChapter 10, Problem 10.47PChapter 10, Problem 10.53PChapter 10, Problem 10.54PChapter 10, Problem 10.55PChapter 10, Problem 10.64PChapter 10, Problem 10.68APChapter 10, Problem 10.72APChapter 10, Problem 10.84APChapter 10, Problem 10.88CPChapter 10, Problem 10.89CPChapter 11, Problem 11.1QQGiven info: The vector B→ is 6i^−10j^+9k^ and vector A→ is −3i^+7j^−4k^ The formula to calculate the...Chapter 11, Problem 11.20PChapter 11, Problem 11.38PChapter 11, Problem 11.46APGiven info: The mass of particle is 76.0 kg , the distance from the ground of its center of mass is...Chapter 11, Problem 11.49APChapter 11, Problem 11.51APChapter 11, Problem 11.61CPChapter 12, Problem 12.1QQChapter 12, Problem 12.9OQGiven info: The mass of the rod is m1=6.00 kg , the mass of the right triangle is m2=3.00 kg , the...Chapter 12, Problem 12.14PChapter 12, Problem 12.20PChapter 12, Problem 12.40APChapter 12, Problem 12.42APChapter 12, Problem 12.51APChapter 12, Problem 12.56APChapter 12, Problem 12.66CPChapter 13, Problem 13.1QQChapter 13, Problem 13.9OQChapter 13, Problem 13.3PGiven info: The mass of the satellite is 1000 kg and the initial altitude is 100 km . The final...The initial speed of the vehicle is vi, the escape speed of space vehicle is vesc and the height of...Chapter 13, Problem 13.60APChapter 13, Problem 13.61APThe maximum distance from the Earth to the Sun is 1.521×1011 m and the distance of closest approach...The mass of the satellite is 100 kg. The initial altitude of the satellite is 200 km and the final...A object of mass m is distance from the Earth’s center is 1.20×107 m. Figure I Formula to calculate...Chapter 13, Problem 13.79CPChapter 14, Problem 14.1QQChapter 14, Problem 14.15PGiven info: The cross sectional area A1 of the left arm of the U-tube is 10.0 cm2 and the cross...Chapter 14, Problem 14.27PChapter 14, Problem 14.44PChapter 14, Problem 14.48PChapter 14, Problem 14.50PThe mass of the balloon is 0.250 kg tied to a uniform length 2.00 m and mass 0.050 kg. The balloon...Chapter 14, Problem 14.64APChapter 14, Problem 14.68APChapter 14, Problem 14.78APChapter 14, Problem 14.80APChapter 14, Problem 14.85CPChapter 15, Problem 15.1QQChapter 15, Problem 15.12PChapter 15, Problem 15.13PChapter 15, Problem 15.19PChapter 15, Problem 15.28PChapter 15, Problem 15.30PThe formula to calculate amplitude is, A=Lθ Here, L is the length of pendulum and θ is the displaced...Chapter 15, Problem 15.44PChapter 15, Problem 15.47PChapter 15, Problem 15.73APChapter 15, Problem 15.76APChapter 15, Problem 15.79APChapter 15, Problem 15.84CPIn a transverse wave the disturbance in the medium is perpendicular to the direction of propagation....Chapter 16, Problem 16.3OQGiven info: The wavelength of wave is 2.00 m , the amplitude is 0.100 m . The speed of wave in...Chapter 16, Problem 16.15PChapter 16, Problem 16.20PChapter 16, Problem 16.27PGiven info: The scalar quantity A is 4(7+3) . The formula to calculate scalar quantity A is,...Any function is a solution of linear wave equation in general if it satisfies the equation...Given info: The linear density of string is 0.500 g/m and tension on the string is 20.0 N . The...The wave function for string is given as, y(x,t)=(A0e−bx)sin(kx−ωt) Formula to calculate the...Chapter 17, Problem 17.1QQGiven info: The speeds of the source and observer are 25 m/s respectively. Formula to calculate the...Chapter 17, Problem 17.18PChapter 17, Problem 17.29PChapter 17, Problem 17.32PChapter 17, Problem 17.41PChapter 17, Problem 17.57APChapter 17, Problem 17.58APGiven info: The young’s modulus of steel is 20×1010 N/m2 , the density of the steel is 7.86×103...Given info: The speed of the train is 25.0 m/s , the distance of the car is 30.0 m and the frequency...Chapter 17, Problem 17.72CPExplanation: When two pulses travel in the opposite direction then the pulses cancel each other in...Chapter 18, Problem 18.1OQChapter 18, Problem 18.2PChapter 18, Problem 18.11PChapter 18, Problem 18.13PChapter 18, Problem 18.17PChapter 18, Problem 18.18PChapter 18, Problem 18.46PChapter 18, Problem 18.70APChapter 18, Problem 18.73APChapter 18, Problem 18.76APExplanation: Given info: The frequency of wave is f , the amplitude of wave is A . The period of...Explanation: The situation in which there is no exchange of energy between the two objects in...Chapter 19, Problem 19.17PGiven info: The initial volume of aluminum cylinder and turpentine is 2.000 L , the initial...Chapter 19, Problem 19.54APChapter 19, Problem 19.57APChapter 19, Problem 19.72CPChapter 19, Problem 19.73CPChapter 19, Problem 19.74CPChapter 19, Problem 19.76CPGiven Info: The length of the rod is 1.00 m , the temperature change of the rod is 100.0 °C . The...Chapter 19, Problem 19.78CPExplanation: Given info: The mass of each sample is 1.0 kg temperature of each sample is 10.0°C ....Chapter 20, Problem 20.8OQChapter 20, Problem 20.15PChapter 20, Problem 20.21PChapter 20, Problem 20.40PChapter 20, Problem 20.61APExplanation: Given info: The mass of one bullet is 12.0 g , mass of second bullet is 8.00 g , speed...Explanation: Given info: The radius of copper disk is 28.0 m , thickness of copper disk is 1.20 m ,...Chapter 20, Problem 20.73APGiven info: The mass of the copper block is 1.60 kg , the initial velocity of the copper block is...Chapter 20, Problem 20.81CPChapter 20, Problem 20.82CPChapter 21, Problem 21.1QQGiven info: The initial temperature of an ideal gas is 300 K and the final temperature of an ideal...Chapter 21, Problem 21.32PSpeed of molecule 1 is 3.00 km/s, Speed of molecule 2 is 4.00 km/s, Speed of molecule 3 is 5.80...Chapter 21, Problem 21.51APChapter 21, Problem 21.55APGiven info: Density of spherical particle is 1.00×103 kg/m3 , temperature is 20.0°C and diameter of...Chapter 21, Problem 21.62APChapter 21, Problem 21.65APValue of average speed is vmp50.0. Write the expression for the Maxwell-Boltzmann speed distribution...Chapter 22, Problem 22.1QQChapter 22, Problem 22.30PChapter 22, Problem 22.32PChapter 22, Problem 22.33PChapter 22, Problem 22.67APChapter 22, Problem 22.68APChapter 22, Problem 22.70APChapter 22, Problem 22.73APChapter 22, Problem 22.76APChapter 22, Problem 22.78APChapter 22, Problem 22.81CPChapter 22, Problem 22.82CPChapter 23, Problem 23.1QQChapter 23, Problem 23.1PChapter 23, Problem 23.12PChapter 23, Problem 23.18PChapter 23, Problem 23.25PChapter 23, Problem 23.38PChapter 23, Problem 23.41PChapter 23, Problem 23.44PChapter 23, Problem 23.54PChapter 23, Problem 23.69APChapter 23, Problem 23.72APChapter 23, Problem 23.85CPChapter 23, Problem 23.89CPChapter 24, Problem 24.1QQChapter 24, Problem 24.28PChapter 24, Problem 24.32PChapter 24, Problem 24.35PChapter 24, Problem 24.42PChapter 24, Problem 24.54APChapter 24, Problem 24.57APChapter 24, Problem 24.60APGiven info: Consider the field distance r<R from the centre of a uniform sphere positive charge...Chapter 24, Problem 24.63CPChapter 25, Problem 25.1QQChapter 25, Problem 25.10PChapter 25, Problem 25.13PChapter 25, Problem 25.17PChapter 25, Problem 25.18PChapter 25, Problem 25.54APChapter 25, Problem 25.55APChapter 25, Problem 25.56APChapter 25, Problem 25.59APChapter 25, Problem 25.66APChapter 25, Problem 25.71CPChapter 26, Problem 26.1QQChapter 26, Problem 26.12OQChapter 26, Problem 26.20PChapter 26, Problem 26.23PChapter 26, Problem 26.26PChapter 26, Problem 26.34PChapter 26, Problem 26.40PChapter 26, Problem 26.50PChapter 26, Problem 26.56APChapter 26, Problem 26.77CPChapter 26, Problem 26.78CPChapter 27, Problem 27.1QQChapter 27, Problem 27.8PGiven Info: The cross-sectional area of iron wire is 5.00×10−6 m2 and the electric current is 30.0 A...Chapter 27, Problem 27.32PChapter 27, Problem 27.33PChapter 27, Problem 27.60APChapter 27, Problem 27.62APChapter 27, Problem 27.63APChapter 27, Problem 27.64APGiven information: Length of the cylindrical wire is 0.500 m , diameter of the cylindrical wire is...Chapter 27, Problem 27.75APExplanation: Given information: Th first symbol i.e. Euler’s number is e , the second symbol i.e....Chapter 28, Problem 28.1QQChapter 28, Problem 28.11PChapter 28, Problem 28.12PChapter 28, Problem 28.16PChapter 28, Problem 28.19PChapter 28, Problem 28.23PChapter 28, Problem 28.34PChapter 28, Problem 28.60APChapter 28, Problem 28.65APChapter 28, Problem 28.74APChapter 28, Problem 28.75APChapter 28, Problem 28.78APChapter 29, Problem 29.1QQChapter 29, Problem 29.8OQChapter 29, Problem 29.10PChapter 29, Problem 29.14PChapter 29, Problem 29.28PChapter 29, Problem 29.44PGiven info: The number of turns in the rectangular coil is 80 , magnetic field is 0.800 T , electric...Chapter 29, Problem 29.52PChapter 29, Problem 29.59APChapter 29, Problem 29.78CPChapter 29, Problem 29.79CPChapter 30, Problem 30.1QQChapter 30, Problem 30.14PGiven Info: The current flowing through the conductor is 2.00 A , distance between corner of square...Chapter 30, Problem 30.16PChapter 30, Problem 30.19PChapter 30, Problem 30.21PChapter 30, Problem 30.35PChapter 30, Problem 30.47PChapter 30, Problem 30.66APGiven info: The amount of current flow in infinitely long wire is 8.00 A and the distance between...Explanation: Given info: The given figure is shown below: Figure (1) Write the expression for the...Chapter 31, Problem 31.1QQChapter 31, Problem 31.12PGiven info: The length of the rectangle is 1.00 m , the value of b is 10.0 A/s , the value of h is...Given info: The radius of the upper circle is 5.00 cm , the radius of the lower circle is 9.00 cm ,...Chapter 31, Problem 31.49PChapter 31, Problem 31.58APChapter 31, Problem 31.61APGiven Info: The number of turns in the rectangular coil is 60 , the dimensions of the coil is 0.100...Chapter 31, Problem 31.78APChapter 31, Problem 31.80CPChapter 31, Problem 31.83CPChapter 32, Problem 32.1QQGiven info: value of resistance R is 4.00 Ω , inductance of the circuit is 1.00 H and emf of the...Chapter 32, Problem 32.26PChapter 32, Problem 32.30PGiven Info: The inductance in the circuit is 140 mH , the resistance in the circuit is 4.90 Ω and...Explanation: Given info: The inductance of the inductor is 3.30 H , the capacitance of the capacitor...Chapter 32, Problem 32.60APExplanation: Given info: The induced voltage is 10.0 V , the resistance of the resistor is 4.00 Ω...Chapter 32, Problem 32.70APChapter 32, Problem 32.75APExplanation: Given info: The battery emf is 18.0 V , inductance is 0.500 H , first resistance is...Chapter 33, Problem 33.1QQChapter 33, Problem 33.24PChapter 33, Problem 33.59APGiven info: The resistance of the circuit is 200 Ω , the inductance of the circuit is 663 mH , the...Chapter 33, Problem 33.66APChapter 33, Problem 33.67APChapter 33, Problem 33.72APExplanation: Given info: The value of resistance is 150 Ω , value of inductance is 0.250 H , value...Chapter 33, Problem 33.76APChapter 33, Problem 33.77CPGiven info: The maximum value of voltage is 100 . The value of the inductance is 2.00 H , the value...Explanation: Given info: The rms potential difference of an AC source is 120 V . Formula to...Explanation: During the discharging of RC circuit, the capacitor contains displacement current....Chapter 34, Problem 34.4PExplanation: Given info: The linear density of the rod is 35.0 nC/m and the speed is 1.50×107 m/s ....Chapter 34, Problem 34.42PChapter 34, Problem 34.46PChapter 34, Problem 34.54APChapter 34, Problem 34.60APChapter 34, Problem 34.67APChapter 34, Problem 34.70APGiven info: The weight of the black cat is 5.50 kg , the weight of the kittens is 0.800 kg , the...Explanation: Given info: The frequency of the wave is 90.0 MHz and the peak value of the electric...Chapter 34, Problem 34.77CPExplanation: While recording videos for movie the camera is focused at some distance from the actor...Explanation: Given info: The wavelength of sound wave is 589 nm and angle of incidence is 13.0° ....Chapter 35, Problem 35.17PChapter 35, Problem 35.28PGiven info: The index of refraction for violet light in silica flint glass is 1.66 and that for red...Given Info: Explanation: Write the expression for snell’s law for prism to calculate angle of...Explanation: Given info: The condition for light ray travelling between air and a diamond is shown...Chapter 35, Problem 35.49PChapter 35, Problem 35.52APChapter 35, Problem 35.59APExplanation: Given Info: The light of wavelength 589 nm is incident on the polystyrene block of...Explanation: Given info: The refractive index of the material is n . Τhe radius of the curvature of...Chapter 35, Problem 35.84CPChapter 36, Problem 36.1QQChapter 36, Problem 36.9PChapter 36, Problem 36.27PExplanation: Given info: The radius of curvature of the curved plastic is 2.25 m . The refractive...Chapter 36, Problem 36.44PChapter 36, Problem 36.46PChapter 36, Problem 36.50PChapter 36, Problem 36.75APChapter 36, Problem 36.77APChapter 36, Problem 36.78APExplanation: Given info: The initial position of the object is 0 cm , the focal length of the...Given info: The diameter of the spherical light bulb is 3.20 cm an the power of light bulb is 4.50 W...Chapter 36, Problem 36.94CPChapter 36, Problem 36.95CPChapter 37, Problem 37.1QQChapter 37, Problem 37.2OQChapter 37, Problem 37.9PChapter 37, Problem 37.18PChapter 37, Problem 37.20PChapter 37, Problem 37.26PChapter 37, Problem 37.36PChapter 37, Problem 37.60APChapter 37, Problem 37.70APChapter 37, Problem 37.73CPChapter 38, Problem 38.1QQChapter 38, Problem 38.4PChapter 38, Problem 38.12PChapter 38, Problem 38.27PChapter 38, Problem 38.28PChapter 38, Problem 38.31PChapter 38, Problem 38.32PChapter 38, Problem 38.48PChapter 38, Problem 38.59APExplanation: Formula to calculate the angles of bright beams diffracted from the grafting is,...Explanation: Given info: The equation of the intensity of the light in the diffraction pattern is...Chapter 38, Problem 38.77CPChapter 39, Problem 39.1QQExplanation: Given info: The speed limit is 90.0 km/h and the fine for driving at 190 E is $80.0 ....Chapter 39, Problem 39.49PChapter 39, Problem 39.59PChapter 39, Problem 39.61PChapter 39, Problem 39.62PChapter 39, Problem 39.65PGiven info: The speed of an electron is 0.750c . Write the equation of kinetic energy of proton....Chapter 39, Problem 39.69APChapter 39, Problem 39.71APExplanation: Given info: The given equation is K=(11−u2/c2−1)mc2 . The equation for the kinetic...Chapter 39, Problem 39.88CPChapter 39, Problem 39.91CP

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