Carbamide peroxide

Catalase, was 50% concentrated (see Fig.3). However, all of the rates were fairly similar no matter the concentration, except for the test with 0% concentration. That test resulted in no production of Oxygen because there was no enzyme for the Hydrogen peroxide to react to so nothing occurred in the testing container (see Fig. 1). In Fig. 2, you can see that all of the concentrations, aside from 0% concentration all produced very similar amounts of Oxygen even though there was not as much of the enzyme

In this experiment concerning the activity of enzymes we tested the different effects of various concentrations, pH, Temperature, and Inhibitors over intervals of time. For the effects of concentration of enzyme extract, or peroxidase we mixed six of seven tubes to get three different concentrations of extract. By doing this we wanted to know whether the concentration would positively or negatively affect the activity of the enzyme, in which we predicted that the concentration would increase the

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will cause the potato enzyme to decompose the most hydrogen peroxide? In order to find the answer to this inquiry, experimenters started the procedure by preparing four different potato samples, where there were, hot, cold, room temperature, and baked potato samples. Each sample was half of two Idaho potato, which was cut into fourths. Then, each group of potatoes were examined when each section was submerged in 150 mL of hydrogen peroxide in individual beakers. The results were recorded based on

values and temperature affect the enzyme activity of peroxidase. Hydrogen peroxide is a byproduct of metabolic feedback in majority of the living organisms.However,hydrogen peroxide is harming to molecules in the cells.Subsequently,nearly every organism produce the enzyme peroxidase,which breaks down hydrogen peroxide as it is formed.Peroxidase can be obtained from from potatoes.The breakdown of hydrogen peroxide into water and gaseous oxygen is aided by peroxidase.This reaction can be distinguished

The purpose of this lab was to better understand the workings of the catalase enzyme when used in substrates (hydrogen peroxide), whilst experimenting with different factors that may affect the result of the reaction. All experiments and activities A, B, C, and D accept the hypothesis given for that activity. Hypothesis A stated if the catalase is added to the hydrogen peroxide, then the product of the chemical reaction will be water and oxygen. By following the experiment procedure, we can conclude

Part A was just a beginning. The experiment showed us what a normal catalase reaction really is. We had one basic procedure; observe what happens when you add hydrogen peroxide to beef liver. At first we were just amazed by the bubbling product, we did not realize that a chemical reaction was going on. We had to redo the experiment so we could note that heat was being released as well as a combination of harmless gasses. We timed the reaction and learned to estimate the reaction rates by the time

yeast enzyme reaction. It was hypothesized that enzymatic production would reach a peak at around 6-8 pH, and then fall again. The original yeast peroxidase solution contained 4 mL of distilled water, 5 mL of yeast suspension, and 1 mL 3.0% hydrogen peroxide. Acids and bases were added to the solution in order to achieve the desired pH. While there were complications leading to a shortage of data, the results pointed to a peak of enzymatic activity between 6 and 8 pH. This suggested that the hypothesis

job of a catalase is to take hydrogen peroxide, or H2O2, and hydrolyze it into oxygen gas, O2 and water, H2O. All enzymes are made so that there is an active site, and the active site is made so that only a certain substrate can bind with it. In this case, hydrogen peroxide is the substrate and the catalase is the enzyme. The hydrogen peroxide fits right in the active site of the catalase. It's a perfect fit, and catalase makes it easier to break hydrogen peroxide into oxygen and water. A catalase

affect the reactivity of catalase? If we add water to the to the hydrogen peroxide, then the reaction will not be as extreme as the control group because the hydrogen peroxide will be diluted. If we add HCl to the hydrogen peroxide, then the reaction will be stronger than the control group because the acids are working together. In this experiment the independent variable was the HCl and water added into the hydrogen peroxide (10 ml each). The dependent variable is the rate of reaction measured in